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Relativity and Cosmology

This is a Blog on relativity and cosmology for engineers and the like. You are welcome to comment upon or question anything said on my website (http://www.relativity-4-engineers.com), in the eBook or in the snippets I post here.

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Cosmic Balloon Application IV: Tethered Galaxy

Posted July 06, 2009 12:00 AM by Jorrie
Pathfinder Tags: cosmology Tethered galaxy

The so-called 'tethered galaxy' thought experiment has created a lot of cosmic interest in the past. It is a rather complex issue with significant pedagogical value, but it is surprisingly easily and simply handled by the cosmic balloon analogy.

Button on a Balloon

The best balloon variant of the 'tethered galaxy' thought experiment has been suggested by StandardsGuy before. I use it with a slight modification here. Pick any spot on a partially inflated cosmic balloon's surface and attach one end of a tether (string) there. Call this spot the origin of the coordinate system. At the other end of the tether, attach a button lying frictionless on the surface - the button is now 'tethered' to the origin at a distance D from it.

Increase the inflation of the balloon from radius R0 to R in time Δt, as in Fig. 1 (right). Assuming that the tether does not stretch with the skin of the balloon, the button will follow the red space-hyperspace vector, being pulled across the surface of the expanding balloon. Without a tether, the expanding balloon would have taken the button along the blue space-hyperspace vector and hence increased the distance from the origin at the Hubble velocity (H D). The starting angle between the blue and the red vectors represents a negative peculiar velocity (relative to the skin), although the button stays at a constant proper distance (D) from the origin - in other words, the tethered button has zero proper velocity. (These are important terms and I shall be asking questions later.)

The Curves

Now cut the tether, so that the button (galaxy) becomes 'untethered'. Wait some time and observe what happens to the proper distance of the button. We need no more than the 'decay of particle momentum' of the previous Blog entry to predict what will happen to the button relative to the origin.

It depends on how the balloon is being blown up. For simplicity, let's first control the gas input rate so that it keeps the expansion rate (dR/dt) of the balloon constant. Starting the simulation at the present age of the cosmos, the curves in Fig. 2 (right) result. For clarity, let's take things step by step, starting with the graph title.

(i) Case (0,0,0) means zero matter, zero radiation and zero vacuum energy density. This gives a constant expansion rate (dR/dt = constant) over all of time. Although not a realistic case, it is a good, simple starting point for understanding the various terms and dynamics.

(ii) The blue D_proper curve is essentially constant at a distance 0.5 Gly (note the y-scale Gly/10). It means that the button's peculiar velocity (across the balloon surface) towards the origin is canceled by the balloon's expansion that is trying to carry it away from the origin. The slight apparent drop over time is just a numerical integration error (only 1000 steps over the 500 billion year time span were used).

(iii) The V_Hubble curve drops down in a typical inverse of time fashion, because for a constant expansion rate the Hubble constant (H) changes proportional to 1/t. Think of a very large balloon that expands at the same rate (dR/dt) than a very small balloon. Since the Hubble constant is recession rate divided by distance, the large balloon will have a much smaller H.

(iv) V_proper is zero in this case, because the proper distance is constant. Proper distance and proper velocity are measures of the instantaneous distance and recession speed of an object. It is as if we use a tape measure and synchronized clocks to find the distance and separation rate between two points on the balloon's surface over a very small time interval.

(v) The green V_peculiar curve represents the (negative) velocity of the button relative to the local balloon surface. The conservation of angular momentum (discussed in the previous Blog) causes the curve to approach the time axis asymptotically. Because the expansion rate is constant in this case, V_peculiar also changes proportional to 1/t. V_peculiar + V_Hubble = V_proper = 0 in this case, so V_peculiar is a mirror image of V_Hubble around the time axis. This is not generally true for more realistic cases, though, as will become clear later.

I suggest that interested readers first 'digest' this information and ask questions as required, before we move on to slightly more complex cases. These Blog posts are necessarily compact, cryptic issues for discussion, so do not be afraid to ask questions. There is no thing like a 'dumb question' - the only 'dumb thing' is not to ask!

Due to some questions asked, here is the (presently) realistic case.

Realistic Expansion

For the more realistic case with present matter energy 26% and vacuum energy 74% of the critical energy density, the balloon is blown up with an accelerated expansion (dR/dt gets larger with time at present). In Fig. 1 above, the distance D remains constant. Here it is to be expected that the faster-growing expansion will drive the button farther from the origin, despite its peculiar velocity towards the origin. V_peculiar now decreases, while V_Hubble quickly starts to increase.

Fig. 3 (right) shows the same curves as for Fig. 2 above, but for the realistic scenario, again starting at the present cosmic age. What is surprising is how "quickly" (in cosmological terms) the proper velocity (red) of the button starts to 'follow the Hubble flow', i.e., how quickly the peculiar velocity of the button decays to near zero.

Some other salient points on this chart:

(i) The V_Hubble line first dips a little, because the Hubble constant initially decays faster with time than the away movement of the button happens. In this scenario, the Hubble constant drops from ~ 74 km/s/Mpc and it settles to a constant ~ 63 km/s/Mpc in another 13 billion years or so. Hence, the Hubble constant eventually becomes a true constant.

(ii) V_peculiar of the button (relative to the balloon skin) remains negative, i.e., towards the origin. The increasing expansion rate does however quickly carry the button farther from the origin. Conservation of angular momentum relative to the center of the ever larger-growing balloon decays the peculiar velocity to zero over time (approaching zero as time tends to infinity).

The above case untethers the galaxy at the present cosmic age. The curves become a bit more complex if the untethering is done much earlier, as shown below.

Multiple epoch case

Here we postulate some 'early universe astronomer' that untethered the galaxy when the cosmos was less than a billion years old. Matter density still largely dominated the cosmic expansion (until vacuum energy took over) and the expansion rate first decreased and later increased. It results in the quite complex (but very interesting) curves of Fig. 4 (right).

At cosmic time t = 0.2 Gy after the BB, the tethered galaxy was at D = –0.1 Gly.[1] At that stage, the expansion rate was decreasing under the dominant (99.96%) influence of matter density of the time.

The Hubble velocity at D=-0.1 Gly was a whopping –0.335c and hence the peculiar velocity of the tethered galaxy at that time was 0.335c towards the origin. But, due to the decreasing expansion rate, the Hubble velocity quickly diminished for that proper distance and hence when untethered, the galaxy started to 'fall' rapidly towards the origin. It 'fell through' the origin at some 1.5 billion years and then continued to move in the positive D direction.

The proper velocity (red) started at zero (because the galaxy was tethered). When untethered proper velocity increased rapidly until the galaxy passed through the origin and then the proper velocity started to decrease – that is for as long as matter density dominated and the expansion rate slowed down.

At around 7 Gy, the acceleration of expansion caused by the constant vacuum energy density more or less balanced out the deceleration of expansion caused by the decreasing matter density. During this time the expansion rate remained more or less constant and the proper velocity of the galaxy also remained constant.

After 8 Gy age the vacuum energy started to win the 'tug-of-war' and the expansion rate started to increase (and so did the proper velocity of the galaxy). During all this, the peculiar velocity (green) continuously decayed and will keep on doing that. The proper velocity eventually joins the Hubble velocity, as before.

Jorrie

Notes:

[1] The tether here had to be a solid rod, not a string, because for a decreasing expansion rate, the tether must actually have keep the galaxy from 'falling' towards the origin. This is essentially a 'cosmic tidal force' at work. More about that in a future Blog post.

[2] Here are some of the equations used (for those who just cannot live without them). Actually, it's good to have a compact set of reference equations for the curves (for my own selfish purposes).

V0 = -H0D0 ---------------(1)[a]

ψ0 = D0/R0 ---------------(2)

L = R0 V0/√[1-V_H02/c2] = constant ---------------(3)

V_peculiar = L/√[L2 + R2] ---------------(4)

D = D + R ψ + V_peculiar Δt ---------------(5)

ψ = ψ + V_peculiar Δt/R ---------------(6)

H = H0 √[Ωm/a3 + Ωv] ---------------(7)[b]

da/dt = a H ---------------(8)[c]

V_Hubble = H D ---------------(9)

V_proper = V_Hubble + V_peculiar ---------------(10)

Footnotes:

[a] V0 of Eq. (1) is the initial peculiar velocity of the button and is specific to the tethered galaxy scenario.

[b] H is the time varying Hubble constant, also sometimes denoted H(t).

[c] a is the expansion factor, R/R0.

-J


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#1

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/07/2009 9:33 PM

Hi Jorrie,

Good post as usual. I see you invited me to respond in the last sentence. The 'drawings' of this post make it much clearer to 'view' the situation as compared to the previous discussion about tethering. The first figure is clear as far as it goes. In the second one, D_proper is shown as flat. If I assume that the 'reference' button is on the center line of the hyper-dimension, then the two buttons behave the same as if they are still tethered? That is not shown in the first figure, so it's not as clear. Your text seems to say that: "the button's peculiar velocity (across the balloon surface) towards the origin is canceled by the balloon's expansion that is trying to carry it away from the origin."

This is not what I would have expected. I would have expected it to be somewhere between the red line and the blue line. I take it that momentum is keeping it there? The previous thread is used as an explanation. Correct me if wrong. There the momentum is from an object at the same point as we are in space. Here the 'buttons' are far apart on the balloon's surface. Aside from that, I'm not sure the analogy works for momentum anyway. I don't think anybody knows what causes it, so expansion of space may reduce it by a different factor.

I'm also confused by the v_proper line in figure 2. It looks like you are defining it to be zero, which would mean that the buttons are still tethered?!? Otherwise it makes sense. Straighten me out if you can.

-S

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#2
In reply to #1

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/07/2009 10:59 PM

Hi S, no you are the one that never shy away from asking, making good points as you go. I was talking to others...

"If I assume that the 'reference' button is on the center line of the hyper-dimension, then the two buttons behave the same as if they are still tethered? That is not shown in the first figure, so it's not as clear."

In this case of uniform expansion (no deceleration or acceleration), yes, the moving button will behave as if it is still tethered, although it was cut loose. Remember that I've attached the string to the origin, so the 'origin button' never moves space-wise. Remember also that the red button was given a peculiar velocity by the string that was precisely equal to the Hubble velocity at that distance.

"I take it that momentum is keeping it there? The previous thread is used as an explanation. Correct me if wrong. There the momentum is from an object at the same point as we are in space. Here the 'buttons' are far apart on the balloon's surface."

Remember, peculiar velocity is relative to the local balloon surface, wherever the button happens to be. In order for angular momentum relative to the balloon's center to remain constant, the peculiar velocity decays as per the green curve. At the same time Hubble velocity decays in identical fashion, so the balance is maintained and the red V_proper curve stays zero for ever.

These are crucial concepts; that's why the simplest case (uniform expansion) must be fully understood before we can carry on.

-J

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#3

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/08/2009 9:38 PM

Hi Jorrie,

"It is a rather complex issue with significant pedagogical value"

I'm not sure what you had in mind here, but I think this could be a useful teaching (pedagogy) tool. It occurred to me that this explains (the theory of) why galaxy diameters do not expand with the universe expansion. You have implied in past threads that this analogy works even in an infinite universe. The data suggests that we have one. Let's see if we can prove that the analogy works for an infinite universe.

Here's the mathematical challenge if you can accept it. So angular momentum is responsible in the balloon analogy for keeping the buttons (stars within galaxies in this case) from moving apart as the universe expands. Now let's represent the universe as a cylinder with constant diameter which expands by getting longer (easy to visualize). Let's say it is 1Gly long to start and expands to 2Gly. The buttons could be 0.1Gly apart to start, then un-tethered. Now they have 'linear' momentum toward each other with respect to expanding space. Do they still maintain the same proper distance after 2Gly?

-S

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#4
In reply to #3

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/08/2009 11:33 PM

Hi S. Your "It occurred to me that this explains (the theory of) why galaxy diameters do not expand with the universe expansion" sounds a bit off the mark to me.

It is just like the button diameter that does not increase (expand), being held constant by molecular forces. The stars in a galaxy are like the molecules of the buttons, with molecular forces replaced by gravity. There is a feeble 'tidal force' on galaxies in a universe with changing rate of expansion, but utterly negligible compared to gravity.

On your 'cylinder analogy'. Yes, you can represent a piece of an infinite, flat universe like that - it's more or less like taking a small section of skin of a very large balloon, where you cannot observe the curvature.

"Let's say it is 1Gly long to start and expands to 2Gly. The buttons could be 0.1Gly apart to start, then un-tethered. Now they have 'linear' momentum toward each other with respect to expanding space. Do they still maintain the same proper distance after 2Gly?"

Yes, but only in the hypothetical 'constant expansion rate' case (which represents an empty universe (0,0,0)). Perhaps I should have given the realistic case plots as well, but I thought it 'good pedagogy' to treat the simplest case first. In the realistic case, the button starts to move away from the origin virtually immediately, provided we are in an increasing expansion rate phase. Here is the graph, without much explanation (which I will do in the main article soon).

Jon and myself have discussed the "cosmic tidal force" issue in that long thread "A blast from the past" (I think). In a nutshell, accelerating expansion does weaken gravity a teeny-weeny bit on the scale of a galaxy, but it is still negligible even at those distances.

-J

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#5
In reply to #4

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/10/2009 12:34 AM

Hi Jorrie,

"The stars in a galaxy are like the molecules of the buttons, with molecular forces replaced by gravity."

To me the orbiting from gravity seems the same as tethering. One object is accelerating the other "toward" it. I was not getting into whether atoms or molecules expand.

"you can represent a piece of an infinite, flat universe like that - it's more or less like taking a small section of skin of a very large balloon, where you cannot observe the curvature."

But I was asking if the same math applies to angular and linear momentum? If it does, then you have proved that the balloon analogy works on an infinite universe! If not, are you using angular momentum math on your small section of skin?

Me: Do they still maintain the same proper distance after 2Gly?"

You: "Yes, but only in the hypothetical 'constant expansion rate' case (which represents an empty universe (0,0,0))"

Wouldn't the same apply to when there is matter but vacuum energy that exactly cancels the gravitational pull?

-S

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#6
In reply to #5

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/10/2009 2:24 AM

Hi S.

"To me the orbiting from gravity seems the same as tethering."

Yes, I suppose one can think like that, but since the buttons themselves are galaxies here, I still think the molecular forces are the best analogy. One can obviously think of a group of buttons as a galaxy cluster, being kept in orbit by tethers.

"But I was asking if the same math applies to angular and linear momentum?"

This is a bit tricky, because linear and angular momentum are not the same thing, so the math is not the same in general. However, the decay of peculiar velocity on the balloon and in a perfectly flat universe is exactly the same. For the hypersphere, we can work with the conservation of angular momentum relative to the center and get the law for the decay of peculiar velocity. In a perfectly flat universe, there is no such center...

However, as I've said to Roger before, for a flat universe it is accepted[1] that one can choose any R larger than the Hubble radius and do your calculations in spherical coordinates. The results are not in the least influenced by the radius that you choose.

I would still not say that "the same math applies to angular and linear momentum?", but rather that the spherical math gives the proper answers for a spherical as well as for a flat cosmos.

You previously: "Now they have 'linear' momentum toward each other with respect to expanding space. Do they still maintain the same proper distance after 2Gly?"

Me "Yes, but only in the hypothetical 'constant expansion rate' case (which represents an empty universe (0,0,0))"

You: "Wouldn't the same apply to when there is matter but vacuum energy that exactly cancels the gravitational pull?"

No, this not generally true. Proper velocity becomes temporarily constant in such a case, but the proper distance will only remain constant if proper velocity remains zero, which is not generally the case in the 'middle ages' of the universe. My next update of the article will include the 'middle ages' epoch of expansion.

-J

[1] Profs. Peebles and Peacock both mention this in their respective cosmology text books.

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#7
In reply to #6

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/10/2009 6:48 AM

I wrote: "My next update of the article will include the 'middle ages' epoch of expansion."

Done it. See OP.

-J

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#8

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/10/2009 2:44 PM

Hi Jorrie,

"Yes, I suppose one can think like that, but since the buttons themselves are galaxies here, I still think the molecular forces are the best analogy. One can obviously think of a group of buttons as a galaxy cluster, being kept in orbit by tethers."

I was trying to say you have a 'teaching aid' here, and it applies to more than whole galaxies. I can understand your 'tunnel vision' here because galaxies are what you are concentrating on.

Just looked at your updates above. Fig 4 is very interesting but I am also confused by it.

"The Hubble velocity at D=-0.1 Gly was a whopping –0.335c and hence the peculiar velocity of the tethered galaxy at that time was 0.335c towards the origin. But, due to the decreasing expansion rate, the Hubble velocity quickly diminished for that proper distance and hence when untethered, the galaxy started to 'fall' rapidly towards the origin. It 'fell through' the origin at some 1.5 billion years and then continued to move in the positive D direction."

I assume that the scale on the left side is only for distance, since you stated the Hubble velocity was -0.335c at -0.1 D. How can distance be negative? Do you mean that the two galaxies collided, and then by momentum kept going and separated going the opposite direction? That would be possible without many stars colliding. The real kicker here is how did the galaxies get separated in the first place if they are coming together then?

-S

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#9
In reply to #8

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/10/2009 8:14 PM

Hi S.

"I assume that the scale on the left side is only for distance, since you stated the Hubble velocity was -0.335c at -0.1 D."

No, I just used a bit of 'zoom' for effect (better curves), so we can't see the whole of the scale. The velocity scale is 1:1, while the distance scale is D/10 as indicated. I will change the picture in the OP to show the whole velocity scale. Thanks for the tip

"How can distance be negative?"

On the cut through the balloon (Fig. 1), negative D is just to the left, since we are doing our sums in 1-D space here.

"Do you mean that the two galaxies collided, and then by momentum kept going and separated going the opposite direction?"

No, it assumes that they have moved cleanly through each other, without effecting each other in any way, not even gravitationally. Maybe I should have just called them buttons (or particles) and not galaxies, because I totally ignore their masses. The idea of the whole thought experiment is to show the peculiar and proper movements of particles caused by expansion in a homogeneous cosmos. Hmm... Better description required.

"The real kicker here is how did the galaxies get separated in the first place if they are coming together then?"

The thought experiment placed them apart, tethered them and then cut the tether. I can see you think gravitational interaction between two galaxies here. This is not part of the thought experiment. We may have to think about a different, massless, collisionless setup. Cosmologists use it as I did, but I agree that it may be confusing to the 'uninitiated'.

-J

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#10
In reply to #9

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/10/2009 11:49 PM

Hi Jorrie,

The graph is much clearer now with the scale matching the description.

Me: "Do you mean that the two galaxies collided, and then by momentum kept going and separated going the opposite direction?

You: "No, it assumes that they have moved cleanly through each other, without effecting each other in any way, not even gravitationally."

That's basically what I said, or tried to say, when I stated that no stars would collide.

"The thought experiment placed them apart, tethered them and then cut the tether. I can see you think gravitational interaction between two galaxies here."

O.K., I did this late last night, and was confusing the thought experiment with the real universe. Still one confusion issue: It starts out with D_proper negative. I thought you always start with the reference on the origin and the other one positive. Why not this time, or am I more confused than I think?

-S

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#11
In reply to #10

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/11/2009 12:51 AM

Hi again, S.

"That's basically what I said, or tried to say, when I stated that no stars would collide."

I later realized that you have thrown me a curve-ball here and I've missed it! I originally described the experiment thus:

"Pick any spot on a partially inflated cosmic balloon's surface and attach one end of a tether (string) there. Call this spot the origin of the coordinate system. At the other end of the tether, attach a button lying frictionless on the surface - the button is now 'tethered' to the origin at a distance D from it."

Only one button (galaxy), a tether and an origin, perhaps with an observer, but no galaxy. So the issue does not really exist.

"It starts out with D_proper negative. I thought you always start with the reference on the origin and the other one positive."

I've done this to let the main graphs of Figures 3 ad 4 progress in the same upward direction (it is after all the sane basic scenario, just over different timescales). The reference is still the origin...

-J

PS: S, do you now feel confident enough to take the "Cosmology-4-Engineers' exam?

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#12
In reply to #11

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/11/2009 10:36 AM

Hi Jorrie,

"Only one button (galaxy), a tether and an origin, perhaps with an observer, but no galaxy. So the issue does not really exist."

Err, I see. I'll use the 'late a night' excuse again. So what did you use, a 'sky hook'?

"I've done this to let the main graphs of Figures 3 ad 4 progress in the same upward direction (it is after all the sane basic scenario, just over different timescales). The reference is still the origin..."

Right, origin is vertical, horizontal is ... <walks away mumbling>

"do you now feel confident enough to take the "Cosmology-4-Engineers' exam?"

But teacher, it can't be test time again yet! I may need more study time. Well, OK, bring it on, if I fail I fail.

-S

P.S. My dog ate my homework!

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#13
In reply to #12

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/12/2009 11:48 PM

Hi S.

"P.S. My dog ate my homework!"

Ah, I think some extra homework should then be in order.

1. Two buttons, both presently at rest in the CMB frame (zero peculiar velocity) and 0.2 Gly apart, are suddenly tethered to each other with a 'perfectly rigid' tether. What will the initial force per unit of mass of the buttons be on the tether?

2. ...

OK, this is not easy, so do not try and give a numerical answer; just say what you think will happen.

-J

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#15
In reply to #13

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/13/2009 7:50 PM

"1. Two buttons, both presently at rest in the CMB frame (zero peculiar velocity) and 0.2 Gly apart, are suddenly tethered to each other with a 'perfectly rigid' tether. What will the initial force per unit of mass of the buttons be on the tether? OK, this is not easy, so do not try and give a numerical answer; just say what you think will happen."

If I read your charts and descriptions properly, then in the case of the (0,0,0) universe there will be stretching force. In the (0.26,0,0.74) case there will be compression force up to 1.5 Gly, and then stretching force will take over. In the (0,0,0) case there may be a contradiction because in order have force between the buttons they would need mass, correct? But it is defined as having no mass.

-S

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#17
In reply to #15

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 12:51 AM

Hi S, OK, it was a trick question and you threw me back a 'trick answer'

No, the buttons are not massless, otherwise they must be treated as photons! We have to consider their masses negligible from a gravitational point of view, otherwise the dynamics differ from what we have here, but not massless.

Let's accept this for now and postulate what could have happened. Before tethering, the two buttons would be moving apart at H0 D = 72/978 x 0.2 ~ 0.015c, i.e. very, very fast! It would hence have been impossible to tether them without something breaking. Before tethering, we would have had to attach rockets to the buttons (or at least to one of them) and boost them to temporarily have zero relative velocity.

Once tethered, we may read the strain gauges. You have it close, but not quite right. In the (0,0,0) case we would have read zero stresses in the tether, because the proper velocity of untethered buttons would have remained zero as in Fig. 2. In the (0.26,0,0.74) case, I have it that the compressing force would have lingered until around 7 Gy of age and then slowly reverse to a stretching force.

At the present time, that stretching force will be equivalent to 0.66 pico-g, or 6.6 x 10-12 N per kg of button mass. Tiny! OK, replace the button with a galaxy and it is a different kettle of fish! The next blog will elaborate on this.

-J

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#27
In reply to #17

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 7:52 PM

Hi Jorrie,

I think you changed the scenario just to confuse me.

"It would hence have been impossible to tether them without something breaking. Before tethering, we would have had to attach rockets to the buttons (or at least to one of them) and boost them to temporarily have zero relative velocity."

We haven't worried about 'impossible' things before! If we assume an unbreakable tether, then as you implied there would be a lot of force! After the rockets (which countered the force), I agree there would be zero stress then. In the (0.26,0,0.74) case, I looked at d_proper but should have looked at v_proper which shows deceleration until around 7 Gy of age and then acceleration from then on. Do I get half credit?

-S

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#28
In reply to #27

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 8:37 PM

Hi S.

"Do I get half credit?"

Yes I think you deserve a lot of credit for persisting on these issues until resolved! You have this one perfectly correct now.

Now for the next question.

Still thinking about it...

-J

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#14

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/13/2009 3:45 PM

Hi Jorrie,

Wanted to return to the other post, and will, but I saw you posted something new and wanted to give it a read.

Let me start by saying that I really appreciate the equation section and I know it's probably a pain, but if you could include such sections more ofter I think it would be really helpful.

That said, can you, when you have a chance, name the cosmology variables/constants (H0, Ωm, a,etc.) Basically the variables that you know on sight but some of us may have to run off to wikipedia to remember what they are. For example (H0 is the Time Independent Hubble Constant).

Ok, my thoughts on your post

I have a few questions.

You Wrote:

V_peculiar = L/√[L2 + R2] and L = R0 V0/√[1-V_H02/c2] = constant

Shouldn't you use the time dependent hubble constant in the equation for conservation of angular momentum with respect to expansion above? I ask because in your "multiple epoch case" your peculiar velocity seems to decline nice and steadily despite the fact that expansion accelerates, then decelerates, than starts accelerating again. It seems like the decline in the peculiar velocity, while always declining, should decline faster, than slower, than faster again.

Also,

I think I understand V_peculair (velocity without expansion considerations or contributions) and I think understand V_hubble (velocity due only to expansion), but can you explain to me what V_proper is? I understand proper distance is the distance on a spacetime graph. I can imagine that V_proper is how distance changes over time on a spacetime graph. Fisrt, is everything I just said right? If it is, why does the proper velocity behave the way it does in your multiple epoch graph?

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#16
In reply to #14

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 12:19 AM

Hi Roger, you wrote:

"V_peculiar = L/√[L2 + R2] and L = R0 V0/√[1-V_H02/c2] = constant

Shouldn't you use the time dependent Hubble constant in the equation for conservation of angular momentum with respect to expansion above?"

Since angular momentum L is a constant for a given particle, we just calculate it once, at the starting position of the experiment (R0 & H0 in this case). Thereafter L is used to obtain V_peculiar for other R, as shown.

You wrote: "It seems like the decline in the peculiar velocity, while always declining, should decline faster, than slower, than faster again."

It may be imperceptibly so, but in essence, the peculiar velocity is not directly influenced by the acceleration of expansion - it depends on 1/R alone, provided the velocities are non-relativistic, i.e., the de Broglie wave energy is small compared to the rest mass.

On proper velocity, yes, you have it correct. On the reasoning behind it, I thought I had it pretty well covered in the last three para's of the article. Remember that the button went from negative D, through the origin, to positive D. It behaves more or less like you wanted peculiar velocity to behave...

-J

PS: S is putting together a cosmological glossary, which should be a nice reference. However, I'll add a bit of definition to the OP.

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#18
In reply to #16

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 1:37 AM

You Wrote:"It may be imperceptibly so, but in essence, the peculiar velocity is not directly influenced by the acceleration of expansion - it depends on 1/R alone"

Yes but isn't 1/R directly related to the expansion rate, especially in the early universe? In your epochs the early inflationary period would have had tremendous 1/R changes. Isn't that true? I would think during that time we would see a sharper decline in peculiar velocity.

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#19
In reply to #18

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 2:26 AM

Hi Roger,

" Isn't that true? I would think during that time we would see a sharper decline in peculiar velocity."

Correct, but this is exactly what the graph shows. V_pec slope goes more vertical the closer you go towards time zero. What I implied is that it follows a precise 1/R curve, irrespective of expansion rate changes. This is required by the conservation of angular momentum principle.

Plotted against time, like I did, the curve is also virtually 1/t, with only tiny, imperceptible changes when the expansion rate changes.

-J

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#20
In reply to #19

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 7:27 AM

You Wrote:"Plotted against time, like I did, the curve is also virtually 1/t, with only tiny, imperceptible changes when the expansion rate changes."

Yes, I understand what you did. You plotted it as though there were no changes in the expansion rate. This isn't ok. The expansion rate of the early universe was too high for you to get away with that approximation. What you should have for your Peculiar Velocity graph is something that hugs the axis more due to the much stronger expansion rate in the early inflationary period (I realize some of this period didn't include matter, but it didn't stop on a dime when matter appeared).

1/R for peculiar velocity is an approximation that assumes no change in the expansion rate. I'm not arguing that the modern graph should be altered, for that one you are quite correct that the difference is trivial. However, for your "many epoch" graph I don't think it is and I don't think the approximation you're making is ok. Please think about it more.

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#21
In reply to #20

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 9:21 AM

Hi Roger, you wrote: "You plotted it as though there were no changes in the expansion rate. This isn't ok."

I think you are missing something here. Just to make sure, the first two charts are for the present and future epochs only (as I clearly indicated) and for simplicity do not include earlier epochs. The third chart is plotted from t = 0.2 Gy onward. All three use the full set of equations (no approximations) and the second and third have significant changes in expansion rate.

"1/R for peculiar velocity is an approximation that assumes no change in the expansion rate. "

Firstly, 1/R is a low speed approximation of the relativistic conservation of hyper-spherical angular momentum; it has little to do with whether or not the expansion rate changes.

Secondly, I have not used 1/R anywhere. It just so happens that relativistic conservation of angular momentum on the hypersphere does end up with something that resembles 1/R when the peculiar velocity is moderate.

I think now it's your turn to think some more.

-J

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#22
In reply to #21

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 9:33 AM

Jorrie,

Again. You Wrote:

L = R0 V0/√[1-V_H02/c2] = constant
V_peculiar = L/√[L2 + R2]

In the second equation, how is R changing with time?

Roger

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#23
In reply to #22

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 10:51 AM

Roger, you asked: "In the second equation, how is R changing with time?"

By equations 7 and 8 of the OP equations list. Just integrate da = a H dt and you have a for any time you wish. Then R=aR0, as per note (c).

H = H0 √[Ωm/a3 + Ωv] sorts out the epoch dependencies, with decelerating expansion for the first 7 Gy and accelerating expansion thereafter.

-J

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#24
In reply to #23

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 11:12 AM

Jorrie,

Can you show the plot of R over time (for the .2 GY starting point case)? I think that would be helpful.

Roger

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#25
In reply to #24

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 11:46 AM

Hi Roger,

Plenty of this sort in Relativity 4 Engineers, but here is a more colorful one.

This one is plotted for H0 = 71.9 km/s/Mpc, 26% matter and 74% vacuum energy components.

The present age is 13.66 Gy, with R = 100 Gly, which is an arbitrary scale for convenience. It is for a flat universe, where the actual radius should be infinite.

As you can see, it is not a very remarkable curve at all! Right at t=0.2 Gy, the slope is quite large (some 8:1), but only for a very short time.

-J

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#26
In reply to #25

Re: Cosmic Balloon Application IV: Tethered Galaxy

07/14/2009 12:49 PM

You Wrote:"As you can see, it is not a very remarkable curve at all! Right at t=0.2 Gy, the slope is quite large (some 8:1), but only for a very short time."

So if you used this varying radius over time (R) to construct your peculiar velocity curve it should be correct then, which is what I think you are saying you did.

The curve doesn't appear to be remarkable because of the long timescale. For most of the history of the universe, d2R/dt2 has been small. If you were to restrict the curve from .2 Gy to .5 Gy, I imagine it would be quite remarkable since the d2R/dt2 over that time was large.

I'm intrigued by the massive decline in momentum that occurred in the early universe (< 1 My). Every massive particles must have been traveling at extremely high speeds (like .999 c or something).

I look forward to your post on the Cosmic Tidal Force.

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