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Join Date: Jun 2008
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Equivelant moment of inertia

06/17/2008 9:08 AM

A speed reducing gearbox has a ratio of 15:1, an input rotor with a moment of interia of 35 kg m(squared) and output roto with a moment of interia of 95 kg m(squared). What is the equivelant moment of interia if the output rotates at 700 RPM?

Can anyone offer any help,

I don't have a clue how to work this question out!!!!!!!!!

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#1

Re: Equivelant moment of inertia

06/17/2008 4:11 PM

Are you asking about the reflected moment of inertia of the output rotor through the gearbox to the input? Ideally (which isn't real), the apparent mass moment of inertia at the input is 1/15 of its actual value, but moments of inertias of gearbox components have to be considered too. The speed of the output rotor doesn't change any mass' moment of inertia, but angular momentum changes with angular velocity.

This help?

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#2

Re: Equivelant moment of inertia

06/17/2008 11:12 PM

"output roto with a moment of interia of 95 kg m(squared). What is the equivelant moment of interia if the output rotates at 700 RPM?"

See Wikipedia for "Moment of Inertia" which is a summation of the distance r^2 x m of each individual particle of mass.

The momentum of the rotating mass is a gray horse of another color (grey?)

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#3

Re: Equivelant moment of inertia

06/18/2008 1:57 AM

If you consider the mass moment of inertia being calculated relative to the output shaft then:

35 kg*m² * 15² + 95 kg*m² = 7970 kg*m²

Mass moment of input shaft must be multiplied by the ratio squared and added to the mass moment of the output shaft.

If considering the mass moment of inertia being calculated relative to the input shaft, then:

95 kg*m² / 15² + 35 kg*m² = 35.422 kg*m²

So mass moment of inertia is dependant on which shaft you consider when having a gearbox with a ratio <>1 (most gearboxes do). In this case both values are related by a factor 15² (= 7970 / 35.422)

Mass moment of inertia is independant of rotation speed.

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