The problem is as follows
The volumetric composition of dry atmospheric air is below
Nitrogen 78.09%
Oxygen 20.95%
Argon 0.93%
Carbon dioxide 0.03%
with the above composition the molecular weight of air comes to 28.97gm/gm-mol.
Now if the air contains about 1.3% water vapour at RH-60% and 34deg C, what shall be the molecular weight of wet air and the oxygen content % by weight. Please provide with suitable method of calculation with answers.
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GVK
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