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Associate

Join Date: Jan 2009
Location: Saudi Arabia
Posts: 39

### Natural Logarithm

12/28/2009 7:33 AM

Hi gents.

please follow the step i have did to solve the following eqauion with natural log, Is it true??? I am confuing because there is a graph and the result does not mach

Pathfinder Tags: ln log
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Guru

Join Date: Mar 2007
Location: City of Light
Posts: 3311
#1

### Re: Natural Logarithm

12/28/2009 12:06 PM

1/JD = ln( Bxe/lx)+ln(π/Cfd+e^(1/JD)lx/Bxe) = ln[(Bxe/lx)*( π/Cfd+e^(1/JD)lx/Bxe)]=

= ln[(Bxe/lx)*( π/Cfd)+ (Bxe/lx )*e^(1/JD)*lx/Bxe)]=

= ln[(Bxe/lx)*( π/Cfd)+ e^(1/JD)]

e^(1/JD)= (Bxe/lx)*( π/Cfd)+ e^(1/JD) → e^(1/JD)(1-1)= (Bxe/lx)*( π/Cfd)

Error in the equations: "Jd" cannot be determined if data at start are correct!

Guru

Join Date: Jul 2007
Posts: 4397
#2

### Re: Natural Logarithm

12/28/2009 1:02 PM

Try that 5th line again, lad.

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"Well, I've wrestled with reality for 35 years, Doctor, and I'm happy to state I finally won out over it." Elwood P. Dowd
Power-User

Join Date: May 2008
Posts: 382
#3

### Re: Natural Logarithm

12/29/2009 7:28 AM

the sum of logs are not the log of sum...

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