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pelican2
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Join Date: Apr 2012
Posts: 14

Overcoming Dynamic Load

05/10/2012 11:27 PM

I need to calculate Electrical effort (or HP) required in overcoming a dynamic load of 50Kgf @ 2 Mtr radius.

This is a metal cutting operation by a Milling cutter. Cutter diameter 110 mm , Depth of cut 4 mm , feed 0.2 mm , Tensile of material being cut is 52Kg/mmsq.
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Tornado
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#1

Re: Overcoming dynamic load

05/10/2012 11:39 PM

At least we know this is not a homework problem; unless to describe how the information is insufficient.

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lyn
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#2

Re: Overcoming dynamic load

05/10/2012 11:46 PM

Why would you need this information? Are you building a milling machine?

#7
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Tornado
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#3
In reply to #2

Re: Overcoming dynamic load

05/10/2012 11:59 PM

Maybe for grooving, facing, or finishing flanges?

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pelican2
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#4
In reply to #3

Re: Overcoming dynamic load

05/11/2012 1:49 AM

You guessed it right,buddy.
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PWSlack
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#5

Re: Overcoming dynamic load

05/11/2012 3:34 AM

Well, the electrical effort will come out as a rate of doing work. There is no rate information in the input data about the metal cutting operation.

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MUKULMAHANT
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#6

Re: Overcoming Dynamic Load

05/12/2012 8:42 AM

Face Mill operating on a Boring Mill?

Less than Half circle Milling? Entering from one edge ?

Cutter RPM ?

Feed 0.2mm-PER CUTTER turn?

Means you are removing max(22/7x110x0.2)/2 = 5mm3/turn? You can work THAT OUT.

Dynamic Load ?--Is the job not stationary - and cutter head Pillar moving at ?

What is the Problem?

mm
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pelican2
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#7
In reply to #6

Re: Overcoming Dynamic Load

05/13/2012 1:08 AM

Face Mill operating on a Boring Mill - No. a machine by itself

Less than Half circle Milling - No. Full circle

Entering from one edge - No. Plunge start.

Cutter RPM - 145

Feed 0.2mm-PER CUTTER turn - 0.2 mm/tooth (half cutter dia) = face width

Means you are removing max(22/7x110x0.2)/2 = 5mm3/turn? You can work THAT OUT - - Pls do with data provided and mention same in KW or HP or Joules.

Dynamic Load ?--Is the job not stationary - and cutter head Pillar moving at -

- Job stationary , Cutter arm turning (hence dynamic load)

What is the Problem?
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kirannawathe
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Location: India,Pune
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#8
In reply to #7

Re: Overcoming Dynamic Load

05/13/2012 4:22 AM

Use trippining type cutter. Decrease the feed. Work in stages leaving bridges. Use magnates for support for the cut parts. The forces will be within the machines capacity.

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pelican2
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#9
In reply to #8

Re: Overcoming Dynamic Load

05/13/2012 7:08 AM

I need to know/calculate the hp or power reqmnt to run the machine. The machine needs to be built. It is not an existing piece of equipment.
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MUKULMAHANT
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#10
In reply to #9

Re: Overcoming Dynamic Load

05/13/2012 9:29 AM

You need restating Problem with Cross sections /Dimensions/ Infeeds sequentially--at least.

I planned complex machining for 20 years. I cannot even visualize what you are looking for.

CNC milling will solve all ----http://www.cncinformation.com/CNCBlog/diy-cnc-tutorial-1-how-to-calculate-steps-per-inch/.

mm
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pelican2
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#11
In reply to #10

Re: Overcoming Dynamic Load

05/13/2012 9:56 PM

Nice to know we share the same passion.

If you give me yr mail ID I can send you AutoCAD/PDF drgs to show my intentions re machining work an proposed method.

Would also like to know yr earlier/present works/activities and yr geographical location.
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MUKULMAHANT
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#12
In reply to #11

Re: Overcoming Dynamic Load

05/13/2012 10:18 PM

CR4 may not like ID showing.

They prefer internal mails to me - Do that.Shall tell U all

mm
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pelican2
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Posts: 14
#13
In reply to #12

Re: Overcoming Dynamic Load

05/15/2012 9:44 PM

In the field of technical matters - especially being purely only technical and without commercial considerations , I dont understand your statement. Anyway , if interested and you have a passion for peculiar technical issues related to a particular expertise , you know where to reach me.

My mail ID is pelicanmachines @ gmail.com.

Let's see now what happens. I mean no ill will and am sure shall not get any.
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Users who posted comments:

kirannawathe (1); lyn (1); MUKULMAHANT (3); pelican2 (5); PWSlack (1); Tornado (2)

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