Buy a second charger and be done with it.

I think they are looking for a way to seamlessly switch between the two chargers...i.e., a circuit that does this for them.

Thanks for the comment

Already bought the 2000 w transformer 220 v to 110 v ac need a full bridge rectifier diode like 10 A rating and a capacitor for the filter just want the values

This is a back up since the 110 v dc charger had always malfunction

thanks

totoalas

You do realize that if you full-wave rectify & smooth 110VAC (RMS) you'll get about 150VDC, yes?

Thought that it will remove the ripple ??? also will an unregulated FWBR be enough to supply the control circuit protection relays of an 11 KV panel????

thanks

1. http://en.wikipedia.org/wiki/Rectifier#Rectifier_output_smoothing

2. Sorry, no idea without knowing what the components are and doing lots of Googling.

Ok Il give more details

We have a 110 v 10 Amperes DC Charger that acts as UPS and at the same time supply the 110 v dc supply to the auxillary panel of 11 KV control / protection relays

and air circuit breaker my aim is to isolate the system during failure / malfunction and supply a tranformer fed 110 v dc with 10 amperes rating to match the 110 v dc charger

hope this makes some clarity

A capacitor will not remove ripple. It can only reduce the ripple.

As for your protection relays, all I can say is maybe.

Agree on that , my aim is to clip or trim the voltage to 110 v dc to match the same output from the 110 v dc charger

Generators and chillers are critical to our operation and a malfunction of these chargers give us a lot of headache .. want to reduce the downtime by supplying temporary power while we rectify the problem of charger / battery failure

thanks

Dinesh m I told u 1000 times. U better ask to ur DGM @ how to make powe pack ripple free nd shall act whenever its operation is required.. i'm serious hez champ in construction. Power. I'm sure he can make ur power pack

Please translate into English.

Maybe these guys got something you need.

http://www.simplypowersupply.com/Rack-Mount-Power-Supply/110Vdc-Output/default.aspx

Read the PDF:

http://www.simplypowersupply.com/pdf/PSS.pdf

Thanks for the link

We currently have 50 pieces and seriously considering a permanent back up ( without charging function). A clean/ stable 110 v dc is all we require

As we are located in China, a proto type which we will be doing IN House can easily be fabricated and cost effective for replication once tested ......

Control Relays are rated at 110 v dc including protection relays from Siemens so we prefer to do it in house for one proto type for mobility in corrective maintenance

The chart is a great help thanks

totoalas

You can use Schade's curves to determine what the filtered voltage (V_C rms) will be for a given a.c. voltage and frequency (ω=2∏f), source resistance R_S (dc resistance of secondary plus diode drops for rectifiers), filter capacitance and a given load resistance R_L.

The way you use this curve is first calculate your R_S:R_L ratio and find the curve on the right hand side of the plot, then find your ωCR_L along the bottom and where that vertical line intersects the curve from the right and on the left hand side will give you a percentage of V_M(peak voltage of the unrectified a.c. input). In the case of 110 vac, your peak voltage is approximately V_M=155 volts.

Something you need to keep in mind is that a transformer is generally rated in VA not watts. The reason for that is to accomodate reactive loads as well as capacitive filtered rectifiers and other non-unity power factor loads. Capacitively filtered rectified circuits usually have a very high crest factor that varies as a function of your load currents and capacitor size, ESR and bunch of other things. A properly specified power factor correction circuit will improve your transformer utilization but at a cost in complexity.

http://en.wikipedia.org/wiki/Crest_factor

As such, depending on the size and reactance of your load and size of capacitance, the current waveform may look like a train of spikes for light loads with large capacitance to rectified sine wave for heavy loads with small capacitance. The reactive power of your transformer/rectifier/capacitor/load may actually produce higher currents than a simple calculation would indicate. A transformer rated at 2000 VA is not necessarily appropriate for capacitively filtered d.c. load at 2000 watts.

It may work, but be careful.

Good luck with your quest !!

20 Amps FWBR and a 10,000 uf 200 VDC @ the output

This I think will solve the problem

Other comments are welcome

totoalas