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In my previous Blog thread, acceleration of an object under constant external force, we discussed this for an object having pure radial velocity (in the direction of the force). We saw how the Newtonian acceleration F0/mo was diminished by the square of the relativistic time dilation factor, or (sqrt[1-v2])2 = (1-v2), i.e.,

Recall that v is a normalized velocity, expressed as a fraction of the speed of light.
What happens if that object's velocity is not purely radial, i.e., if the velocity vector also has a transverse (or tangential) component. In the figure below, vx is the radial component and vy the transverse component of velocity v.

It can be shown that the relativistic acceleration in this scenario is:

It can be understood as follows: The velocity component in the direction of the force diminishes the force by the velocity time dilation caused by vx only. The mass-energy of the object however increases by the velocity time dilation caused by the actual velocity (v). It is easy to spot that if vy=0, then v=vx and the equation reduces to the one given first above.
This was a 'sneak-peek' out of the final chapter of the eBook Relativity 4 Engineers, where relativity is tackled from grass-roots level.
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