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This is a Blog on relativity and cosmology for engineers and the like. My website "Relativity-4-Engineers" has more in-depth stuff.

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Tidal Prediction Part 1

Posted November 20, 2006 10:00 PM by Jorrie
Pathfinder Tags: Moon cycles Tidal cycles

Coastal tide prediction for any location on Earth is an empirical process, but it is based on very precise astronomical cycles of the Moon and the Sun. The primary cyclic changes are depicted in Fig. 1 below. Because I'm a southern hemispheric, rotations are as seen from far above Earth's South Pole, so it's clock-wise.

First, there is Earth's rotation period of 23h56m against the 'fixed' stars. Then the Moon's orbital period of 27.32 days, with the corresponding change in distance from perigee to apogee. Finally, there is Earth's orbital period around the Sun of 365.25 days, with the corresponding cycles of the seasons due to Earth's inclination to the ecliptic. The orbit is also elliptical and this of course also changes Earth's distance from the Sun based on this one year cycle.

Figure 1

A much less known periodic cycle is the advance of the Moon's perigee with a period of 8.8 years. Shown in Fig. 2 is the change of the orientation of the ellipsoid of the orbit against the distant stars after just 2.2 years. This is an ordinary perigee advance caused by mainly by the Sun's gravity and is not a relativistic effect, which is utterly negligible in the case of the Moon-Earth system.

Figure 2

Probably the least understood, yet pretty important tidal cycle, is the precession of the Moon's orbital plane around Earth. As indicated in Fig. 3 below, the Moon's orbital plane is inclined by 5° to the ecliptic.

Figure 3

Due to the fact that the Moon's orbit is quite elliptical, the Sun's gravity causes this plane to precess like a top relative to the fixed stars. The period is 18.6 years, as shown in 90° steps in Figures 4 to 7 below (the perigee advance of Fig. 2 is ignored here for simplicity).

Figure 4

Figure 5

Figure 6

Figure 7

The 25.8°S has no more relevance than that it was the latitude of the venue where I gave a presentation (to amateur astronomers) using these slides. Some of them were pretty surprised that the Moon sometimes actually passes south of them! It only happens every 18 years or so.

There are even longer cycles, like Earth's spin axis that precesses around a full circle in about 25 thousand years, but they are normally not used in tidal prediction. The result of the primary cycles are that one needs data for at least 18.6 years for every region in order to make good tidal predictions.

In Part 2 of this mini-series I will show some other effects on the tides and then plot a few curves...

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Anonymous Poster
#1

Re: Tidal Prediction Part 1

11/23/2006 12:48 PM

Jorrie, this is all very interesting, but what the heck has this got to do with timing of the tides at my favorite fishing spot?

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Guru
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#2
In reply to #1

Re: Tidal Prediction Part 1

11/23/2006 1:11 PM

Hi Guest, you asked: "... this is all very interesting, but what the heck has this got to do with timing of the tides at my favorite fishing spot?"

This has all to do with your favorite fishing spot, but nobody can help you if you don't tell us where it is!

More seriously, I'm afraid, you will have to wait until after the weekend for the next "installment" - there is a harmonic correlation, but with various offsets!

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The Engineer
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#3

Re: Tidal Prediction Part 1

12/06/2006 5:38 PM

Jorrie,

Does the Sun ever have to be considered in these calculations. The gravitational pull due to the Sun should be much larger than that of the moon. Why doesn't the oceans just bulge outward in the direction of the Sun? High tide at noon and low tide at night?

Roger

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#4
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Re: Tidal Prediction Part 1

12/06/2006 10:35 PM

Hi Roger, you asked: "Why doesn't the oceans just bulge outward in the direction of the Sun? High tide at noon and low tide at night?"

The Sun's normal gravity (GM/r2) is much stronger then the Moon's, but due to the relative closeness of the Moon, it's tidal gravity (~GM/r3) is about twice that of the Sun. So one get a resultant 'tidal vector' rotating around Earth every 25 hours or so, pointing closer to the Moon than the Sun.

And then, there's two highs and two lows per 25 hours in most places! The chapter 'Tidal Gravity' on my website says it all...

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#5
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Re: Tidal Prediction Part 1

12/09/2006 1:19 PM

Interesting, so it's the gradient of the gravitational field that matters rather than the strength. In other words, the amount of gravity one side of the Earth would feel as opposed to the other side. So although the Sun's gravity is larger on Earth, the difference in the Sun's gravity from one side of Earth to the other is a 1/3 smaller the the gravitational pull from the moon on one surface as opposed to the other.

In other other words, the radius of the Earth must be noticeable in terms of the distance, 1/r2 like in the moons case. Though if it was massive enough, the distance that produces and noticeable gradient would be smaller. Thats why the call the forces that rip you apart outside a black hole "tidal forces". Really cool. Am I on the right track here Jorrie?

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#6
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Re: Tidal Prediction Part 1

12/09/2006 3:01 PM

Hi Roger, yep, as you said: "... so it's the gradient of the gravitational field that matters rather than the strength."

A quick check on the download from Tidal gravity, or a quick read in the eBook Relativity 4 Engineers, chapter 9, page 125, will give you a lot more information on this.

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#7
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Re: Tidal Prediction Part 1

12/09/2006 5:03 PM

Ok, I read it and you were right, it answered all my questions. It really is well written.

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