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This is a Blog on relativity and cosmology for engineers and the like. My website "Relativity-4-Engineers" has more in-depth stuff.

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Relativistic Orbits Demystified

Posted June 09, 2008 11:00 PM by Jorrie

This is an 'engineering-view' of relativistic orbits, written in the terms and mathematics that most engineers are comfortable with, yet it is scientifically rigorous. It is an attempt to demystify the rather complex behavior of relativistic orbits.

The relativistic orbit of a particle with mass m at distance r from an uncharged, non-rotating black hole with mass M can be obtained from a set of 'flat space' equations of pseudo-forces[1], a-la Newton's gravity:

Here gtt = 1-2GM/(rc2) , the gravitational redshift factor squared, valid for r > 2GM/c2. Force Fr is the radial gravitational pseudo-force on a particle moving with radial speed vr and transverse speed vt. It is easy to spot that it is the Newtonian force, modified by some relativistic terms. Force Ft is an apparent transverse gravitational pseudo-force on the particle, as is evident from its trajectory - it does not exist in Newtonian gravity. Numerical integration of equations (1) and (2) gives the relativistic orbit.

The origins[2] of these equations will be discussed later, but in brief: the normal Newtonian gravitational force is modified by the curved spacetime through which the orbiting particle moves. It causes additional apparent pseudo-forces on the particle, as viewed in the Schwarzschild coordinate system. Below we will discuss the pseudo-forces term by term and show their effects on the orbit of a particle around a black hole.

For a pure Newton orbit, we simply set c => infinity, hence gtt = 1, Fr = -GMm/r2, Ft = 0 and we have the familiar Kepler ellipse that repeats over and over. The black circle at the focus of the ellipse represents the Schwarzschild (event horizon) radius RH=2GM/(rc2) of the point mass, drawn to scale. The small blue circle represents the particle at time t. The periapsis of the orbit is at 5RH and the (transverse) velocity at that point is vt = 0.3744c, chosen for a convenient orbit size and some other esthetical considerations. All the orbits shown here have these initial conditions and are drawn to the same scale.

If we set c to its normal value, but ignore the influence of velocity, i.e., we only consider the effect of gravitational time dilation (or redshift) gtt = 1-2GM/(rc2), the radial force Fr becomes:

The Newtonian force has been multiplied through for clarity. That positive 2(GMm)2/(r3c2) term reduces the magnitude of the negative Newtonian force and modifies the orbit as shown below.

Apart from a larger ellipticity due to the lesser gravity, there is also a retrograde precession of the orbital ellipse. The closer to the event horizon, the more the Newtonian force is reduced, meaning that the orbit curves less when close to the black hole. This causes the orbit to precess in a retrograde direction.

If we now also factor in the effect or radial velocity vr, while ignoring transverse velocity, we have the radial force as:

The radial velocity term reduces the magnitude of the negative Newtonian force further and gives the orbit an increased ellipticity. The radial velocity does not change the orbital precession appreciably, so the retrograde periapsis shift remains. At the periapsis, the radial velocity is zero, so there the third term vanishes. Near the periapsis it is small, explaining the small effects on ellipticity and precession.

That third term can be viewed as a sort of 'anti-gravity' effect that is proportional to the inverse square of the distance from the hole and to the radial speed of the particle squared. It is however a pseudo force that is due to the curvature of space and the relativistic effects of velocity and sadly, it cannot be used to propel a spaceship.

Next we also factor in the effect or transverse velocity vt, but we keep the transverse force Ft = 0 for now. The radial force equation is now complete:

Note the differences between the radial and transverse velocity terms - apart from the factors +3 and -2 respectively, there is a gtt below the line in the radial term, caused by the fact that radial movement encounters changing spatial curvature, while pure transverse movement stays at a constant curvature.

The fact that the last (negative) term works with the normal negative Newtonian force, drastically reduces the ellipticity of the orbit and surprisingly, it causes the orbital precession to become prograde. This is due to the large value of vt near periapsis, causing a stronger inward force and hence the orbit curves more than in the previous cases. The prograde precession for the particular initial conditions is about 25 degrees per orbit, periapsis to periapsis.

One may think that this is it - there can after all only be radial forces in the symmetrical gravitational field of a 'point source'. Not so in the curved spacetime around a black hole.

Only when we also consider the transverse force, eq. (2) above, do we have the full relativistic orbit. It has an increased ellipticity and an increased pro-grade precession, caused mainly by the transverse pseudo-force. The particular orbit chosen precesses by exactly 90 degrees per orbit, so that after four revolutions it repeats itself, creating a simple four-leaf pattern.

Note from eq. (2) that the transverse force is dependent on the product of the radial and transverse velocities. If the product vrvt is positive, i.e., during the outwards portions of the orbit, the transverse pseudo-force works with the orbital movement. During the inwards portions of the orbit, vrvt is negative and the transverse pseudo-force works against the orbital movement. This balances the energy equations nicely, but it must obviously cause deviations from Newtonian orbits.

It is clear that the transverse pseudo-force causes the bulk of the periapsis precession of relativistic orbits. It is however not a real force, but again an artifact of the Schwarzschild coordinates chosen. While the particle moves in the curved spacetime, its coordinate positions over time correspond to all the pseudo forces discussed above.

It is hoped that this post and possible discussions that may follow will make relativistic orbits a little less mysterious![3]

Jorrie

[1] All Newtonian gravitational forces on a point particle are pseudo-forces, because a freely moving particle does not 'feel' accelerations. It is only when the particle's movement is measured in some static coordinate system that one can deduce that there is a Newtonian forces acting on it. In general relativity, such motion is called geodesic movement and is force-free.

[2] The mathematical details (and a lot of explaining) of the relativistic orbital accelerations are contained in Appendix C of Relativity-4-Engineers.

[3] Also look at the beautiful patterns of the highly relativistic orbit in the previous post in this CR4 Blog again. Note that that 'four-leaf-clover' performs a few close-by, nearly circular orbits around the black hole before zooming out to the apoapsis and back again. The same equations and principles do however apply.

-J

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Re: Relativistic Orbits Demystified

06/12/2008 8:54 PM

Hi Jorrie,

This thread and the last 2 are very interesting. You did a great job on the graphics too. Good work! I have a question (it may be a stupid one). When an orbit is modified by relativity, does the orbit decay (will the object eventually spiral in or lose orbit)?

regards,

S

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Re: Relativistic Orbits Demystified

06/13/2008 1:47 AM

Hi S. "When an orbit is modified by relativity, does the orbit decay (will the object eventually spiral in or lose orbit)?"

Your question is actually rather deep! The equations that I gave are conserving energy and hence there is no natural decay of the orbit.

This is rigorously true for a solo particle orbiting a solo black hole. Once you have a lot of 'particles' of gas and dust, there are collisions and friction causing heating, making them lose orbital energy. They then form an accretion disk that slowly spirals into the black hole, emitting high-energy photons due to the heat.

One can also consider energy loss due to the emission of gravitational waves, but that is only evident when two massive bodies orbit each other and not for particles orbiting a massive thing (where the particles have negligible gravity by themselves).

Jorrie

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