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Anonymous Poster

Power Problem

06/03/2008 11:11 PM

Hello all, I am new here and find this site very helpful.

I have a small problem and hope y'all can help.

I am tasked to come up with the required KVA to support instruments that have a total amperage of 6 amps in our ASU plant in PNG.

How do I calculate the required KVA?

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Guru

Join Date: Feb 2006
Location: Piney Flats, Tennessee
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#1

Re: Power Problem

06/03/2008 11:23 PM
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Power-User

Join Date: Aug 2007
Location: Bhopal India
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#2

Re: Power Problem

06/03/2008 11:24 PM

Welcome Guest,

If you like this site, i wonder what stops you from registering...

anyway you have not provided a very important input, and that is voltage....

you need kva so volts as well as amperes have to be known....right...

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Guru

Join Date: Feb 2006
Location: Piney Flats, Tennessee
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#3
In reply to #2

Re: Power Problem

06/03/2008 11:54 PM

I forgot to sign in is all.

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Guru

Join Date: Feb 2006
Location: Piney Flats, Tennessee
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#4
In reply to #2

Re: Power Problem

06/03/2008 11:56 PM

DID YOU GO ALL THE WAY TO THE BOTTOM OF THAT WEB SITE??

FORULMAS THERE

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Anonymous Poster
#5

Re: Power Problem

06/03/2008 11:57 PM

KVA Rating = Voltage x Current

consider 10 amp insted of 06 amp for factor of safety

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Guru

Join Date: Feb 2006
Location: Piney Flats, Tennessee
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#6
In reply to #5

Re: Power Problem

06/04/2008 12:02 AM

UNDER POWERING DEVICES CAUSES THEM TO HEAT UP AND SHORTEN THEIR USEFUL LIFE. We always supply extra to prevent that damage.

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Member

Join Date: May 2008
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#8
In reply to #5

Re: Power Problem

06/05/2008 7:43 AM

Hi

The method to calculate depends on what is the end use

but for all that we can do is list down all the equipments those are to be powered

Make an Excel sheet and write down in column 1 the name of the equipment

column 2 the voltage for the equipment

coumn 3 the average current

column 4 the Peak current ( starting current in case )

column 5 the Surge current as specified in the operations manual

Column 6 the Power factor

Column 7 now calculate the continuos power required using Average Current (V x A x pf)

Column 8 Caluculate the peak power using the Peak or surge current as the case may be but use whichever is maximum

Now you would get two results one which would help you to design your Power requirement along with the trip setting details and other for continous opeartion giving you details of the HVAC and other requirements.

Trust this would help you.

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#7

Re: Power Problem

06/05/2008 6:55 AM

We need more input. 6 amps at 5v or 6 amps at 13.2KV. It makes a wee bit of a difference. What kind of loads are they? Poor power factor inductive? or closer to unity resistive or somewhere in beween?

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Participant

Join Date: Jun 2008
Posts: 1
#9

Re: Power Problem

06/06/2008 4:05 AM

Thanks, you all for the your replies to my problem.

With your help I have sorted it out - I will be using a 3kVA UPS (10 Amps) to keep the instruments up and safe during power cuts.

Thanks all and I look forward to your assitance in the future.

jonjon

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