I am guessing that the room is extremely hot and you are trying to cool the space. The quick answer is to size a fan to remove air from the room which will remove the hot air allowing outside air to come in making the space cooler.
Standard rule of thumb is 10 air changes per hour. Measure the room, calculate the volume, divide that volume by 60 minutes and multiply by 10 which would give you a flow rate (In volumetric units per minute) with which to size your fan.
The complicated answer would be that you somehow figure out how much heat is being generated and then caculate how much air movement you will need to remove the heat.
While general exhaust ventilation may be a solution to your high ambient temperature condition, depending upon the actual source of the heat in your "process line", it may be much more practical to capture the heat at the point (or points) of generation via LOCAL exhaust ventilation - erecting some sort of canopy or slotted hood to extract the heat directly where it is emanating from.
This could likely be done with significantly less total CFM of air exhaust than with general exhaust ventilation, and could possibly save money due to not having to thermally condition or "temper" the large volume of make-up air supply.
You can obtain some excellent guidance from a "classic" publication in the field of ventilation, by the American Conference of Governmental Industrial Hygienists (ACGIH), entitled: "Industrial Ventilation: A Manual of Recommended Practice"
This book includes numerous tables, diagrams and design drawings for generic and specific process exhaust ventilation set-ups...
What a nice post about Exhaust Fan, I like your post. You are providing nice service. A good ventilation system for your roof
will have an air intake hose along with an exhaust hose.
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