Hi CR4er.I work in a cement plant where we use a lot of belt conveyor.I need to know the formular to calculate the speed of a conveyor belt of a considerable length with a number of counterweight drums and snub drums.
The given examples are great if you need to know all of the variables that will occur through frictional losses etc.
However for practical purposes locate the main drive motor, establish output RPM from nameplate (1400 - 2400RPM). Divide this by any reduction gearbox ratio to establish the drive roller RPM (20:1; 25:1; 40:1; 50:1 etc).
Measure the diameter of the drive roller and work out its circumferance (dia x 3.14).
Now you have established the drive shaft RPM and the lineal distance the belt travels for each revolution.
Multiply the drive shaft RPM x the drive roller circumference to establish the lineal travel of the belt per minute ;-)