Pivoting Cage

I am working on a cage that has to be counter weighted. I had calculated the weight to cage the cage in its working position which 17 degrees below zero or horizontal. The counter weight is 12 inches from pivoting point and the center of gravity of the cage is 6 feet from the pivot point.

Note that this is a safety cage for a truck access dimensions:9'-0" x 12'-1 7/8" inside dimensions. The 2 pivot arms are approximately 7 feet in length, where the arms are attach to the 6 feet from the pivot point at the cage center of gravity of the cage.

I calculated the weight of the counter to bring the cage into equilibrium using 2w=6 times 197, 197 pounds is the weight of cage. Therefore w equals 588 pounds.

What I am trying to find out is when the cage is in its working position at 17 degrees below zero what is the weight I need to rotate the cage to 45 degrees above horizontal to its store position? We found by keep at weight to each side until the cage was 45 degrees above horizontal.

Could someone assist me with the calculation for this projection?