Xc in a circuit

That looks somewhat strange. Is that for a special circumstance where something is assumed? Where did you find this equation?

Dear Guest,

In any electrical circuit when Voltage -V is applied against the impedence Z , then the current-I in the circuit will be V /Z.

Hence I=V/Z

Power consumed P= Ix IX Z eqn-1

=V/Z X V/Z xZ =VxV/z

The Power may be active(P) or reactive (Q)

The load may be resistive (R) or reactive XL or capacitive Xc

In this case the load is capacitor and hence it has Xc as impedence and Power consumed is reactive power ie Q

Hence from eqn-1 , Q= V xV/xc

or Xc= vxv/Q

Hope this clear to you now

V.Ambarani

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Oops. OF brain seizure. When I saw Q and Xc, I immediately thought of Quality Factor. BEEP! Wrong answer. Sorry.

Thank you very much. Thats cleared that up greatly