total load calculation

No clue what you are asking for.

Hi,

there is no relvance for your 24 hours. If we can presume 2880 kW is 24 hours consumption, then what is the supply volatge. If it is 415 V, 3 Phase supply, then the Current can be determined. Accordingly the current rating for individual load can be determined.

Regards,

N.Suresh

HI DEAR

THANKS FOR REPLAY

MY SUPPLY VOLTAGE IS 415 VOLT AC 3 PHASE AND P.F. 0.8 SO PL.REPLAY

THANKS & REGARDS

JIGAR SOLANKI

How are you ?

sir if your voltage is 415V and P.f is 80% so what do you need to know?

but as far as your given data is concerned or my understanding is to unearth the power: 330 +_ 2 watts.

Regards,

ahsum haleem

polymer engineer

if you want to know current is o.8 A.

ahsum haleem

polymer engineer

total load is 518.5 0hms

ahsum haleem

polymer engineer

hi,

sir try it!

kVA = volts (line to ground) X amps X 3 (three-phase system) ÷ 1,000

ahsum haleem

polymer engineer

Dear,

KW is the unit for rate of doing work i.e. power so 2880 per 24 hrs, it isn't concerned.

1. calculate current I which is equal to voltage V / resistance R

2. p= I.I R now put your values I=P/(R.I) this gives you current utilized through whole powersTHEN MULTIPLY THIS I by per unit cost

ahsum haleem

Polymer engineer