Pressure Generator

Is the subject equipment a 'centrifugal pump or liquid ring compressor/vacuum pump'?

How do you want to use the pressure generated and where will you tap into this pressure, is the pump going to do useful work?? is it an enclosed transmission drive with reaction blades??

In order to answer your question without regard to what you want to do:

required: smallest radius where the fluid is moved, outer radius, specific mass. All units have to be correlated.

dp= dm*r*ω^2 dm= 2*π *r*dr*ρ

thus dp= 2*π *ω^2*ρ*r^2*dr

you integrate it from rmin to rmax and get the value you want.

Δp= 2/3*π *ω^2*ρ*(rmax^3-rmin^3)

Pressure difference between rmin and rmax at flow =0

Hope it will help.

ω = rotational speed in radians/second

ρ = specific mass of fluid.

I've looked through my math and available engineering reference books and request some clarity. I'm unsure of the symbolism in the equation.

The meanings or representation of:

d is:

p is:

m is:

^ is:

r is:

n is: pie?

Once I have an understanding of the terms, I should be able to figure out the numbers needed.

Thanks

Kid73049

Sorry for delay but I was out of town (even country) so that it was not possible to answer.

I will answer using my 1st message as base.

dp= dm*r*ω^2 dm= 2*π *r*dr*ρ

thus dp= 2*π *ω^2*ρ*r^2*dr

dp= pressure difderential generated vetween 2 radiuses at "dr" difference

dm= mass element

r= current radius

ω= rotational speed in rad/sec

π= PI ( unfortunately the character is not the best )

ρ= specific mass

you integrate it from rmin to rmax and get the value you want.

Δp= 2/3*π *ω^2*ρ*(rmax^3-rmin^3)

Pressure difference between rmin and rmax at flow =0

Hope it will help.

ω = rotational speed in radians/second

ρ = specific mass of fluid.

Hope all is now clear.

Rgards

Nick Name