Heating Air at Different RH levels

Let me rephrase my question to add the amount of air would be 1 cubic foot.

Do you know how much energy you'd need for that amount of dry air? If you can derive the Mixing Ratio from RH using the partial pressure of the water vapor present at a given RH, you can calculate the actual amount of water in a given sample. (I don't know these relations offhand. If you do, you're ahead of me). From that you could assume you'd need 1 cal/gram of energy to heat the water, plus the energy you'd need to heat the same volume of completely dry air. A place to start looking, at any rate.

-e

Thank you for your help!

A psychometric chart can analyze just about anything you can think of to do with air. Follow this link for how they work;

http://ohioline.osu.edu/aex-fact/0120.html

If you do a search on them you can find one that you can download. You could buy pads of them in the past but I don't know if they are still available.

Type in "Psychrometric Chart" in Google. You get a couple of hundred hits.

Pick one to suit.

You need to decide whether to work in constant pressure or constant volume or constant mass. They are linked by a simple formula: P x V = m x R x T.

P = pressure

V = volume

T = temperature

m = mass

R = gas constant (but it depends on the units used for P,V, T and m)