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Voltage Drop and Power Outlets for 110V

04/02/2009 5:44 AM

hi everyone.

we use 220V/380V in my country but now i have to design 110V project and i have couple of question about that.

1-How can i calculate drop voltage rate??is there any formula for that? For example according to 220/380V calculation it shouldnt be more than %1.5 and formula is %e=200*Length*Power/56*cable size*220*220

2-How many power outlet can i connect on one line??according to 220V standards we can connect max 7 power outlets.

i am waitin ur answers.

thanks

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Power-User

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#1

Re: 110V

04/02/2009 8:31 AM

Dear Akinbaglan,

voltage drop etc. will depend on national standards so you'd better check according to the country you are delivering to. For example, to start with, what we call "110 V" in Brazil is in fact 127 V (phase to neutral voltage, so you get 220 V between phases).

The EU has changed from 220 / 380 to 230 / 400 in around 1988, is it not the same in Turkey now?

best regards

Snel

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#2
In reply to #1

Re: 110V

04/02/2009 8:38 AM

Nope Snel,

We still use 220V/380 system.I will design electrical project for dijibouti in Africa.They want both power outlets(220V and 110V) in building.But i dont have any information about 110V circuit breaker and other materials.

thanks

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Power-User

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#3
In reply to #2

Re: 110V

04/02/2009 9:01 AM

In case 380 is not needed 127 / 220 will be less expensive if acceptable or maybe even usual in Dijibouti.

Circuit breaker specs are again a matter of national standards. IEC breakers ("white", thermoplastic case) are used in conjunction with wiring at a higher temperature. US NEC breakers ("black", thermosetting case) are related to somewhat thicker wiring. Curves can be different, too, but most important is the max short current (100 kA is not so easily found in IEC breakers and large system impedances may be much lower in "110" ).

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#4

Re: Voltage Drop and Power Outlets for 110V

04/02/2009 10:04 AM

Based on NFPA 70, NEC 2008, the calculations in 220.14(I) apply to receptacles. Each 15A or 20A, 125V general-use receptacle outlet is considered as a 180 VA per mounting strap. Assuming that the circuits are 20A, the maximum number of receptacles on a circuit is 13.

Circuit VA = Volts x Amperes

Circuit VA = 120V x 20A

Circuit VA = 2,400 VA

Number of Receptacles = 2,400 VA/180 VA

Number of Receptacles = 13

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#5

Re: Voltage Drop and Power Outlets for 110V

04/02/2009 4:21 PM

Voltage drop is based on Ohms law. Voltage Drop = load amps x resistance of the wire. R of the wire is usually listed a ohms per 1000 ft or in your case it may be meters. The NEC does list 180 kva per location but that is for service calculations.To be accurate you need the actual load. The distance used is 2 x the circuit length to include the resistance of the conductor and neutral.

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#6

Re: Voltage Drop and Power Outlets for 110V

04/02/2009 11:48 PM

You should check which standards you want to use is it American 100V/60Hz or Japanese 100-110/50-60Hz?

The amount of outlets depends on what you are planning to connect, it depends on the fuse (like only one outlet for washing machine) or 4 or 5 for a small room for common electrical appliances.

Just figure out how much VA you are planning to use and add separate fuse-boxes accordingly

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Power-User

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#7

Re: Voltage Drop and Power Outlets for 110V

04/03/2009 6:43 AM

dear,

you require 220/110v ( 1 phase ) auto transformer for step down. with tappings of +/- 5% , 10% as per the voltage fluctuations in africa. If more fluctuations, you may as well have to go for stabilizer.

Voltage drops depend upon your conductor size / length & current expected.

if you want line to line 3 phase 110v, then you require 3 phase auto transformer of

380v 3ph 4 wire / 110v 3 ph 4 wire auto transformer. In this case, you get 63.5 v between line & neutral.

If you want 110 v between phase & neutral with three phase system, you require

Auto transformer of 380v 3ph 4 wire / 190v 3 ph 4 wire with tappings +/- as required.

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#8

Re: Voltage Drop and Power Outlets for 110V

04/03/2009 7:24 AM

K = constant 10.8 ohms per mil foot of copper @ 30 degrees C

L = Total length of circuit to and from the load in feet

I = Total calculated load of the circuit in amps

Vd = Total percent of allowable drop in volts

Cm = Circular mil area of the conductor

Cm = (K*I*L)/Vd

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Active Contributor

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#9
In reply to #8

Re: Voltage Drop and Power Outlets for 110V

04/03/2009 7:29 AM

thanks my friend this is what i asked...

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Power-User

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#10
In reply to #8

Re: Voltage Drop and Power Outlets for 110V

04/03/2009 8:21 AM

dear ,

this is for single phase supply.

for 3 phase suppy,

Vd = 1.732 * I * L * r where I = line current

---------------- L = length of conductor

1000* pf ( 1>pf >0) r = resistance of conductor / km

Vd = volta drop across cable - line - line

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