Gear Reducers

check this link http://www.qtcgears.com/q410/q410cat.htm

Rather simple really.

Divide number of teeth on pinion(driver) into number of teeth on driven gear = reduction ratio :QED ! Beyond this point you are into deep water.

have you any idea about the dia of gear and type of gear.

i think diffrent type of gear have diffrent formulas for reduction.

Machine tool design books by Mehta,

Machine tool design by sen &Battacharya

and few foreign authors will help you

should work on detailed ray diagrams and stuff.

Gear ratio is dependant on the number of teeth of pinion and wheel for every gear type, except for worm wheels.

i = z.pinion / z.gear

There is a direct relation between the pitch diameter and the number of teeth, also taking in account a dimensional factor (module) and the helix angle of the gear tooth.

Pitch Diameter = module * z / cos(helix angle)

The module is the required pitch of the gear, divided by pi. Pitch for pinion and wheel must be equal, otherwise they won't mesh.

In the USA and UK, things are a bit different. They use the diametral pitch ( = 25.4 / module). So

diameter = z / (DP * cos(helix angle)), giving diameter in inches.

It's like a transformer; the further you reduce voltage=speed the more current=torque you'll get.

The ratio is inversely proportional to each other; one factor comes down the other goes up.

Use this online caculator!!! http://www.groschopp.com/Products/Gearmotors/tabid/75/Default.aspx

Kapish?

G.A. from me and v. good answer.

The other night they had a webinar about <1 hp motor efficiency including this topic.

The online calculator (STP) is good to down load to help you.