Metal Cylinders and Thermodynamics

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hmmm...i didnt want an answer.i just wanted to know how to go about doing it . like guidelines or formulas. i don't need answers

OK, this a simple gas law problem.

Google gas laws.

i thought it was more on the equation of P abs = P atm + P g ?

Continue.

yea. so , using the equation above , i can only fill in the value of P atm which is 1 or 101.3 kPa. is there any other equation i should use also ?

waynetan

This has little or nothing to do with thermodynamics. It's simply a case of dividing force by area to get pressure. It doesn't matter whether it's gas or liquid, what the temperature is, or whether the changes are adiabatic or isothermal. These things affect the final volume, but not the pressure.

Cheers.........Codey

thermo is all about setting up your condition states. Determine State 1 Condition: m1=10kg, P1=760mm Hg, V1=0.2m square. Do the same for State 2. Then, solve for the missing variable (Hint, its P2 and Pabs=P2 + 760mm Hg). Drawing a picture of both state always helps..

You have the force you have the area _{and you have DVader} What else do you need for this calculation?

Of course it is not mentioned the process is adiabatic/isothermal/isentropic/ isenthalpic so that portion may be assumed, to be isothermal for simplicity.

I love it when a forum is "self-correcting".