An automobile travels at a constant speed on a highway curve of 1000m radius.If the normal component of acceleration is not to exceed 1.2m/s,what is the maximum allowable speed.
You don't mention the bank of the curve which will effect the maximum allowable speed. Also the vehicle mass, centre of gravity, track and tyre friction, vehicle aerodynamics, etc will likely play a part (unless you want a rough estimate).
If you have a NASCAR track locally you could try it in practice (oh science and physics are so much more fun when you put them into a practical and group-participation context). Fairly safe too as I doubt any of you have a vehicle fast enough to exceed the maximum allowable speed. No beer for the driver thou!
You don't need to take account of that or the factors mentioned in #5. Assuming he meant 1.2 m/s2, it's fairly clear he just wants to know what speed gives that centripetal acceleration (let's take his word that it's not homework!). Formula is acc = V2/r giving V = 34.64 m/s.
By appropriate banking of the track, the net force on the car can be eliminated, but the centripetal acceleration is still there.
Cheers........Codey
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