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dynamics

10/01/2009 12:17 PM

An automobile travels at a constant speed on a highway curve of 1000m radius.If the normal component of acceleration is not to exceed 1.2m/s,what is the maximum allowable speed.

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#1

Re: dynamics

10/01/2009 12:25 PM

Homework alert!!!!!!!!

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#2
In reply to #1

Re: dynamics

10/01/2009 12:39 PM

And bad homework too. Acceleration should be in m/s2

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#3
In reply to #2

Re: dynamics

10/01/2009 2:12 PM

Hey guys, don't be funnyi was trying to figure out something for my group mates.But thanks for your help.

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#4

Re: dynamics

10/01/2009 2:39 PM

Formula for maximum allowable speed:

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)Where:

f = Price of tires (US$)/ Number of windows on car

x = Liter Displacement of powerplant (assume petrol) / Lumens from the moon available

d = Efficiency of driver (represent as decimal)

a = Effective use of parking lot (represent as decimal)

k = Number of beverages available to driver / Number of beverages already consumed by driver

b = Aggravation factor of getting a speeding ticket

This gives maximum allowable speed 299,792,458 meters per second for my car.

Getting a lot of mileage out of this one... No more, I promise.

Adjustments to the formula may need to be made for your actual conditions.

With apologies to Parseval... and just about everyone else too

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#8
In reply to #4

Re: dynamics

10/01/2009 11:12 PM

Thanks

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#5

Re: dynamics

10/01/2009 2:39 PM

<hmmmm>

You don't mention the bank of the curve which will effect the maximum allowable speed. Also the vehicle mass, centre of gravity, track and tyre friction, vehicle aerodynamics, etc will likely play a part (unless you want a rough estimate).

If you have a NASCAR track locally you could try it in practice (oh science and physics are so much more fun when you put them into a practical and group-participation context). Fairly safe too as I doubt any of you have a vehicle fast enough to exceed the maximum allowable speed. No beer for the driver thou!

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#7
In reply to #5

Re: dynamics

10/01/2009 8:17 PM

you also have to take in to affect how much weight is in the "car" as well as how much the driver weighs.

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#10
In reply to #7

Re: dynamics

10/05/2009 5:05 AM

You don't need to take account of that or the factors mentioned in #5. Assuming he meant 1.2 m/s2, it's fairly clear he just wants to know what speed gives that centripetal acceleration (let's take his word that it's not homework!). Formula is acc = V2/r giving V = 34.64 m/s.

By appropriate banking of the track, the net force on the car can be eliminated, but the centripetal acceleration is still there.

Cheers........Codey

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#9
In reply to #5

Re: dynamics

10/01/2009 11:14 PM

Thanks

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#6

Re: dynamics

10/01/2009 5:25 PM

The one indicated in "solutions" chapter of your prof book

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