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I have a pressure gauge ... i calibrate like this way...total gauge span is 0 to 40 bar
actual pressure measured value
10 bar 10.2
20 19.8
30 30.1
40 40.1
how to calculate % error plz advise me
(10.2-10)/(40-0) = ?
(20-19.8)/(40-0)=?
(30.1-30)/(40-0)=?
(40.1-40.0)/(40-0)=?
Which is the largest?
Resolution on the gauge is only 0.1/40!
your comment is wrong. how did you calculated that you know .....!!!!
Actual = 10 and measured= 10.2
Error = 0.2 and % error = 0.5
Every thing is ok. you have to take in both way rising and falling.
% error must be within +/-1 or in some cases +/- 2 ( depends on client)
your gauge is ok...
sudip
It's not my gauge. It's the other Guest's gauge.
What is the zero value?
Depending on the accuracy of the gauge the tollerance could be between 0.1% and 2%
Do the readings duplicate on increasing pressure, referenced to decreasing pressure?
The percent of error is usually expressed as
(the greatest error divided by the actual value -1x100)
10.2/10= 1.02-1= .02 x 100=2%
19.8/20= 0.99-1= -0.01 x 100=-1%
Therfore 2% is the percent of error
Probably the linearity adjustment could be used to improve the calibration significantly
You can probably recalabrate the gauge using the zero adjustment to correct the reading at the point of most intrest. (Splitting the error)
% ERROR is Error divided by span multiplied by 100
what you explained totaly wrong
the performance of the gauge is ok