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s_barbera
Member

Join Date: Oct 2006
Posts: 6

z Transform

01/19/2007 4:06 AM

Hi. When I have an integral in time domain, in Laplace it is F(S)=k/S. Can you tell me the discrete parallelism with z transform? Can I use s=(2/T)*((z-1)/(z+1)) ? And the inverse transform? In the end I need the discrete F[n] expression.

Thanks, Simone.
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cnpower
Guru
Engineering Fields - Control Engineering - New Member China - Member - New Member

Join Date: Sep 2006
Location: CHINA
Posts: 2945
Good Answers: 14
#1

Re: z Transform

01/19/2007 9:46 PM

There are lots of table for you reference. YOu can find them on autocontrol books and relative textbook. Its a basic transform. The k/s is a la's transform of a step function. you can conside it as 1/s for simple form. because either la's or z transform is according to miltify law of constant. so that you can get z form as follow F(z)=z/(z-1) The S and Z is belong to differnt domain, they can mapped each other but cnannt exist in a same domain just like my home is in china and your home is in anohter country. I can go to your country and live your home, vice versa, but our home are in differnt places, not one same home.

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