I have a square metal plate that is fastened down to another metal surface by four M6 socket head cap screws in each corner that are torqued to 55"/lbs. I want to build a fixture with a pneumatic cyclinder (Bimba most likely) that has a 'foot' with four legs attached to the ram that will press down equally over the four screw thru holes. The area in each corner that each individual leg will contact will be no more than the area that the head of each M6 screw contacts as it holds down the plate. What force is needed to equal the force that four M6 screws exert so that I can size my pneumatic cyclinder accordingly? Clear as mud?