Calibration Range for Dp Transmitter

The transmitter must be fitted with both legs connected to the vessel. The low side of the TX should connect to the top of the vessel via a wetleg and must remain full of process (this gives the reference to full level). The high side of the TX is connected to the bottom of the vessel. Your calibration range will be -5800mm H₂O to 0mm H₂O.

Hi,

The formula is P=h x s.g.

If h=5800mm in others words the distance between the bottom tap(high side) and the top tap(low side) is 5800mm then P=5800X0.94 equals 5452 mm of water since this pressure is being applied to the LOW side then this value will be negative.

-5452mm of water is your ZERO or LRV, it can be verified by installing the transmitter legs on their corresponding places and opening them to atmosphere.

To calculate the URV, P=5800mmX1 equals 5800mm of water so to have 100 % level you are going to go 5800mm of water to the positive side starting at -5452mm of water.We do the calculation -5452+5800=+348mm of water.

LRV=-5452mm of water

URV=348mm of water

Span=5800mm of water

Personally when using capillary transmitters I don't figure my zero using the formula I rather install the transmitter and vent both legs then connect my communicator to find the pv value.

I hope this help you I am having problems putting my thoughts in words.

Have a nice day!

The conversion from mm water column to mbar is:

5800 mm water = 568.78 mbar, which is where the range of 569 mbar comes from.

If the units on the transmitter include mbar, then

LRV -5452 mm of water = -534.65 mbar

URV 348 mm of water = 34.12 mbar

The span from -534.65 to 34.12 is 568.77 mbar

Dear

569mbar is equivalen with 5802.185 mmh2o(mmwater)

now I give code for you information,heigh water ( h ) 5800 mm.sg process (sg1 ) 1,sg capillary ( sg2 ) 0.94.heigh of capillrary on lowside (d) 5800 mm

span = h x sg1

= 5800 mm x 1.

= 5800 mmh2o

zero = d x sg2

= 5800 x 0.94

= 5452 mmh2o

Range = -5452 to (5800 -5452 ).or -5452 mmh2o to 348 mmh2o