Please note that Class PS CTs & Class 5 P 10 CTs are not the same. A Class PS CT is not specified the same way as a Class 5 P 10 CT.
Now, answering Mr. Venu:
Your Class PS CT Name Plate will have a specification called "Knee Point Voltage or Vkp". Please note it down.
Vkp = K If (Rct + 2 Rl + RB)
where
Vkp = Knee Point Voltage of the CT, in Volts
K = Constant (normally taken as 2)
If = Maximum Fault Current at the CT Location, as reflected at the Secondary side of the CT, in Amperes
Rct = CT Secondary Winding Resistance, in Ohms
Rl = Lead Resistance of the Connecting Leads from the CT Secondary to the Burden, in Ohms
RB = Resistive Burden of the Connecetd Load, in Ohms
You will know all other parameters. Then you can calculate the Load Burden that can be connected to the CT Secondary. This you will get in Ohms. Now, multiply this resistive burden by the square of the CT rated current. You will get the burden in VA.
This (electricalexpert65's answer) is good answer. The formula is here rewritten for the better clarity:
Vkp = K * If * (Rct + 2 Rl + RB)
Further addition:
PS CTs are specified by
- Turn ratio
- Minimum knee point voltage (Vkp)
- Maximum exciting current at Vkp or at its fraction.
- Maximum resistance of secondary winding.
- MS
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"All my technical advices in this forum must be consulted with and approved by a local registered professional engineer before implementation" - Mohammed Samad (Linkedin Profile: http://www.linkedin.com/in/msamad)
Ohmic Burden of the Relay at the guven setting = VA Burden of the relay at the given setting / Square of the set current
Just to give an example, the VA Burden of Areva Make CAG 14, 1 Ampere Relay at the minimum setting of 10% is 0.9VA. This means the resistive burden of the relay at this setting will be: (0.9) / Square of (0.1) = 90 Ohms.
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