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Burden for PS Class CTs

06/20/2010 6:41 AM

As per the name plate details we are not having the burden details of CT of PS class. That means there is no limit for PS class CT isnt it ?

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#1

Re: Burden for PS Class CTs

06/21/2010 1:05 AM

The CT nameplate should have someting similar to the following:

30/5P 10 and this can be deciphered as follows;

First number designates the burden (Output VA i.e. 30 in this case)

Second number designates Accuracy class (5P in this case)

Last number indicates composite error (10% in this case)

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#2
In reply to #1

Re: Burden for PS Class CTs

06/21/2010 5:15 AM

Sir, i am having a CT with special Class which i have entioned below

Automatic electric/pragati make

Current transformer

single pase type

rated voltage 36kv

service voltage 33kv

rated frequency 50hz

short time current 25kv, 1sec

Bil 170kv(peak)

As given below:

Single core CT

Ratio: 200/1

Class PS, VK>450v,Imax<30mA at VK/2,Rct<3ohms,

For differential protection with relay DTH31.

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#3
In reply to #1

Re: Burden for PS Class CTs

06/21/2010 9:48 AM

Please note that Class PS CTs & Class 5 P 10 CTs are not the same. A Class PS CT is not specified the same way as a Class 5 P 10 CT.

Now, answering Mr. Venu:

Your Class PS CT Name Plate will have a specification called "Knee Point Voltage or Vkp". Please note it down.

Vkp = K If (Rct + 2 Rl + RB)

where

Vkp = Knee Point Voltage of the CT, in Volts

K = Constant (normally taken as 2)

If = Maximum Fault Current at the CT Location, as reflected at the Secondary side of the CT, in Amperes

Rct = CT Secondary Winding Resistance, in Ohms

Rl = Lead Resistance of the Connecting Leads from the CT Secondary to the Burden, in Ohms

RB = Resistive Burden of the Connecetd Load, in Ohms

You will know all other parameters. Then you can calculate the Load Burden that can be connected to the CT Secondary. This you will get in Ohms. Now, multiply this resistive burden by the square of the CT rated current. You will get the burden in VA.

Hope this helps.

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#4
In reply to #3

Re: Burden for PS Class CTs

06/21/2010 12:26 PM

Sir, thats wat i am asking how much RB can i maintain in my circuit

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#5
In reply to #3

Re: Burden for PS Class CTs

06/21/2010 1:16 PM

Thank you for the corrrection. During formulating my reply I totally missed out the point that reference has been made to Class PS (X)

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#6
In reply to #3

Re: Burden for PS Class CTs

06/21/2010 5:54 PM

This (electricalexpert65's answer) is good answer. The formula is here rewritten for the better clarity:

Vkp = K * If * (Rct + 2 Rl + RB)

Further addition:

PS CTs are specified by

- Turn ratio

- Minimum knee point voltage (Vkp)

- Maximum exciting current at Vkp or at its fraction.

- Maximum resistance of secondary winding.

- MS

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#7
In reply to #3

Re: Burden for PS Class CTs

08/12/2010 2:58 AM

what is the different between 1PS CT and PS CT

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#8
In reply to #3

Re: Burden for PS Class CTs

05/10/2012 5:12 AM

--

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#9
In reply to #3

Re: Burden for PS Class CTs

05/10/2012 5:13 AM

Can u pls tell me how to convert the relay burden in to Ohm value.?

Thank you.

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#10
In reply to #9

Re: Burden for PS Class CTs

05/10/2012 9:43 AM

Ohmic Burden of the Relay at the guven setting = VA Burden of the relay at the given setting / Square of the set current

Just to give an example, the VA Burden of Areva Make CAG 14, 1 Ampere Relay at the minimum setting of 10% is 0.9VA. This means the resistive burden of the relay at this setting will be: (0.9) / Square of (0.1) = 90 Ohms.

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