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Anonymous Poster

Faraday's Law

06/27/2010 10:58 AM

so according to faraday's law, the voltage between the conductor terminals of a closed loop of wire is equal to the derivative of the flux through the loop

http://upload.wikimedia.org/math/9/7/a/97acc856d0b23b7fd64872968abef047.png

and then u can make an inductor by making many turns around a core and the equation is the same but with the factoor N

the problem i have with this is that in a dc circuit there is no voltage accross the inductor, which should mean there is no derivative of flux, which means there is no flux, yet it still makes a magnet right?
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kvsridhar
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#1

Re: farradays law

06/27/2010 11:09 AM

Can you explain a little more please ?

An inductor is a number of turns of wire around a ferromagnetic core (can be air-cored also). If you apply a DC voltage, the Steel core becomes a magnet with defined NS poles. If you apply AC to it, Faraday's formula comes alive, and the changing flux induces a voltage opposite to the applied one, depending on frequency and L.

What is your doubt please?

Vader?

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mjb1962853
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Engineering Fields - Electrical Engineering - Analog and Digital Circuit Design Engineering Fields - Electromechanical Engineering - Transformers, Motors & Drives, EM Launchers Engineering Fields - Engineering Physics - Applied Electrical, Optical, and Mechanical

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#2

Re: Faraday's Law

06/27/2010 7:12 PM

Derivative-of-flux may be "0", but that does NOT mean flux is "0". It only means flux is constant. (Is that an oxymoron ? )

http://en.wikipedia.org/wiki/Inductance#Properties_of_inductance

Flux = L * i / N
V = L * di/dt

Voltage (EMF) is caused by the rate-of-change of the current and the current and flux are proportional to each other based on geometric factors.
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Anonymous Poster
#3

Re: Faraday's Law

06/27/2010 9:50 PM

holy crap how could i have been so foolish, tyvm
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