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Anonymous Poster

Wind Speed and RILEM Tubes

07/20/2010 12:07 PM

Does anyone know how the RILEM tube windspeeds are calculated? There is the equation Q (kg/m2) = Velocity*2/16 but I'm not sure how this is derived.

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#1

Re: Wind Speed and RILEM Tubes

07/20/2010 4:47 PM

Excerpt from: WaterSealant.com

The height of the column of water, as measured from the center of the bowl to the

meniscus in the tube, determines the hydrostatic pressure applied to the test area. This

pressure can subsequently be converted into a velocity, or wind-driven rain speed. As

an example, if the tube is filled to the "0.0 mL" graduation, this exerts a pressure of

1139.36 Pa, which correlates to a 98.1-mph wind-driven rain. Filling the tube to the "2.5

mL" graduation correlates to a 78.2-mph wind-driven rain.

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#3
In reply to #1

Re: Wind Speed and RILEM Tubes

07/21/2010 4:23 AM

Thanks "PMoon"

That's very helpful. It looks like a simple calculation to calculate the pressure from the weight of water (i.e. mass*gravity*height)

I was wondering how I could get to the relationship between this pressure and the velocity. Any ideas?

Eric

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#4
In reply to #3

Re: Wind Speed and RILEM Tubes

07/25/2010 7:11 PM

From Appendix C of the National Building Code of Canada, pressure and wind velocity are related by the formula:

q = ρV2/2

where q is the pressure in Pascals, ρ is the density of dry air at 0oC, taken in Canada as 1.2929 kg/m3 and V is wind velocity in m/s.

If you want it in Imperial units, you will need to do the appropriate conversions.

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#5
In reply to #4

Re: Wind Speed and RILEM Tubes

07/26/2010 4:35 AM

Thanks a lot Bruce, that's spot on.

Eric

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#2

Re: Wind Speed and RILEM Tubes

07/20/2010 4:54 PM

Heae's another link I got by Googleing Rilem Tube.

Graduation

Theoretical Wind

Mark (ml)

Speed (mph)

0 98.1
0.5 94.1
1.0 90.04
1.5 85.7
2.0 81.1
2.5 75.2
3.0 71.1
3.5 65.5
4.0 59.4
4.5 52.8
5 44.8
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