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Join Date: Aug 2010
Posts: 10

Short Cicuit KA

08/14/2010 5:46 AM

my qus is that for the calculation of kA of a system it is necessary to select a common base.i mean to ask thatwe just do it for the ease of calculations or practicall it os done?

coz i was calculating the KA of a system and the kva rating of trafo n generator were different.if i dont select the base kVA the total KA of system coming was differenr from the one in which i selected a common base.

i need ur help as i want to select equipments of my system keeping in mind the kA level.

REGARDS
UMAIR RAFIQ

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#1

Re: Short Cicuit KA

08/14/2010 3:31 PM

When equipments operate in a large systems, the generators, transformers and feeders have their %age impidences essentially referred to their respective KVA ratings (all of them may have different ratings in KVA).

In order to compare various impidences (percentage resistances and reactances) and to find out the combined effect, it would be necessary for you to refer them to a common KVA (base KVA).

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#2

Re: Short Cicuit KA

08/14/2010 6:04 PM

Dear Umair,

Please Mention your System requirement KVA and also Short Circuit KA.

I would like to check

Regard's

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#4
In reply to #2

Re: Short Cicuit KA

08/15/2010 1:33 PM

Dear!

i hava six generators each of 1445KVA and a tarfo of 3000KVA!!

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#6
In reply to #4

Re: Short Cicuit KA

08/16/2010 1:42 AM

please provide the Xd" and %Z of the generator and transformer respectively.

also provide the voltage level at which these are connected and voltage level of the generator and transformer.

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#9
In reply to #6

Re: Short Cicuit KA

08/18/2010 10:54 AM

for generator its 0.11 PU

trafo 17%

11kv system!!

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Guru

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#3

Re: Short Cicuit KA

08/15/2010 8:15 AM

There are two basic methods to calculate the short circuit current (viz.) (i) Ohmic Method or Direct Method or Impedance Method and (ii) Per Unit Method.

Only in per unit method, you need to have some base values like Base Voltage, Base MVA and Base Impedance. In direct method, you don't need to convert anything referring to any base values. It is a simpler method.

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#5
In reply to #3

Re: Short Cicuit KA

08/15/2010 1:34 PM

would u like to distinguish b/w per unit and impedance method>?

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Anonymous Poster
#7
In reply to #5

Re: Short Cicuit KA

08/16/2010 3:21 AM

Yes! There are very clear distinctions between the two methods. But, nevertheless, the calculated fault current vales must match.

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Active Contributor

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#8
In reply to #7

Re: Short Cicuit KA

08/18/2010 10:53 AM

can u plz give me an example of calculation !!by pasting a link!!it will help me a lot

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#10

Re: Short Cicuit KA

08/23/2010 11:30 PM

best option is to use the transformer ratings as base values for your system is basically supplied by the transformer after the generator...or if you want to use the generators nameplate ratings..then transform the impeadances...

Znew = Zunit(MVAbase / MVAunit)(KVunit/KVbase)^2

...just recheck fla, i can't recall it further..

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#11
In reply to #10

Re: Short Cicuit KA

08/24/2010 1:45 PM

ok!!can u gimme one more answer!!whilr transformin the per unit impedance of transformer!!which voltage should i consider!LT side or HT side???(i mean what will be the base vol)

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#12
In reply to #11

Re: Short Cicuit KA

08/27/2010 1:15 AM

you can use either of the two...mine, i use the LT voltage for all equipments later on will be supplied from this voltage...

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#13
In reply to #12

Re: Short Cicuit KA

08/27/2010 1:38 PM

how come?the ans will come different wen i use 0.4 kv as unit voltage adn 11kv as unit volatge for exmaple

i have per unit 0.15

base kv=18

unit kv =0.4

base kva=3000

unit kva 1500

ans will come different if i take unit kv as 11kv!!

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#14
In reply to #13

Re: Short Cicuit KA

09/02/2010 12:50 AM

hmm...rate some of your components, the order in which they are served..then ill try solving it..include: impeadances, operating voltage, VA ratings...let me check if i could further convey..

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#15
In reply to #14

Re: Short Cicuit KA

09/02/2010 1:27 PM

consider i m geberating the volateg @ 11kv!!n using the trafo 11.0.4 for auxilaries

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adeebulrehman (1); Anonymous Poster (2); electricalexpert65 (1); mountk2 (1); rockraiden (3); sms149 (1); umair rafiq (6)

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