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Relationship Between Voltage Drop and Power Factor

05/26/2011 3:28 AM

Require Guidance for Cable Voltage Drop with respect to P.F:

% Voltage drop = (1.732X Full Load CurrentX Length (Km)X(Rcos@+Jsin@)X100 )/ (Volt X No of Run)

Ex. For 1.6KM , 50Amp,cos@=0.8,Sin@=0.6, R=0.41Ohm/Km, j=0.074Ohm/Km

% V.D =12%

But if P.F will increase and goes to 0.9 (Cos@=0.9) than

% V.D is 13.40%.

so if System has Good P.F than You have more Voltage drop..If we installed Capacitor Bank to minimise KVAR hece to improve P.F will increase V.D in System..

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#1

Re: Relasionship between Voltage drop and Power Factor

05/26/2011 4:14 AM

Hi,

I better look cable manufacture catalog to find the voltage drop than calculate.

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Guru
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#2

Re: Relasionship between Voltage drop and Power Factor

05/26/2011 5:18 AM

Doesn't seem logical does it? When the pf is 1, the current is the least. It goes up as the pf comes down. The voltage drop depends directly on the current for a given set of conditions. How can it go up as the current goes down?

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#3

Re: Relasionship between Voltage drop and Power Factor

05/26/2011 5:38 AM

Single phase voltage drop:

Vd = 2K x L x I / Cm or Cm = 2K x L x I / Vd

For both examples: Vd = voltage drop, K= 12.9 for resistance for a copper conductor, L = length of circuit in ft., I = current or amps of the load, Cm = area of the conductor in Circular Mills.

Three phase voltage drop:

Vd = 1.73K x L x I / Cm or Cm = 1.73K x L x I / Vd

1 square mm = 1973.52524139 Cm or Circular Mill

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#4
In reply to #3

Re: Relasionship between Voltage drop and Power Factor

05/26/2011 6:09 AM

What has this got to do with the OP???

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Guru

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#5

Re: Relasionship between Voltage drop and Power Factor

05/26/2011 7:36 AM

I fully agree with KVS. When the power factor has improved from 0.8 to 0.9, then definitely the current thro the cable also MUST have reduced from 50 Amps to a lesser value. I think, in your case, you have taken the current as 50 Amps in both the cases.

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