Dear all,
Kindly clarify the following:
I am laying 4 runs of 3*240Sq.mm aluminium cable from drive to motor. I shall be calcualted the cable i^2 losses(250M). In that each cable shall be taken of 300A. So i simply put 300*300*(resistance of 250M) multiplied my no of runs. This is correct or I need find the parrallel reistance of 4 cables. Then AC resistance shall be combination of resitance+reactance.(XL). If resistance will be come down. What about the capacitane value. Kindly explain in detail.
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