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Anonymous Poster #1

Errors In Heat Dissipation Calculation For An Enclosure

08/06/2011 4:34 AM

"The Heat balance, Which Consist of comparing the power released by the devices with the power exchanged spontaneously through the wall of the enclosure, allows us to calculate the internal temperature obtained in the enclosure, with no thermal accessories"

1. Characteristics of the Enclosure

H = Height (m) W = Width (m) D = Depth (m)

H= 2.0 W= 1.2 D= 0.4

Position of the Enclosure Location according to IEC890 ratio Formula for Calculating S (mý)
Accesible from every side S = 1.8 x H x (W + D) + 1.4 x W x D

Placed against a wall S = 1.4 x W x (H + D) + 1.8 x D x H

On the end when suited S = 1.4 x D x (H + W) + 1.8 x W x H

"On the end when suited, Placed against a wall" S = 1.4 x H x (W + D) + 1.4 x W x D


In the middle when suited S = 1.8 x W x H + 1.4 x W x D + D x H

"In the middle when suited, Placed against a wall" S = 1.4 x W x (H + D) + D x H


"In the middle when suited, Placed against a wall with top covered" S = 1.4 x W x H + 0.7 x W x D + D x W




Considering the panel to be placed against a wall
S= [1.4x1.2x(2+0.4)] + (1.8x0.4x2)
S= 5.47 m2

2. Thermal power dissipated by the operational components

A list of electrical components dissipating power is detailed:
Component Details Power Dissipated x number of components Total Power Dissipated (W)
1 Push button and 36 ( 2.4 W lamps) & 3 Selector Switches 1.3x40 52
1 MCCB of 100 A 4P =24x1= 24
1 115A 4P contactor 31x1 =31
22 MCB of 16 A 2P 5.2x22 =114
7 MCB of 25A 4P 6.5x7 =46
1 MCB of 6A 2P 2x1= 2
22 RCCB of 16 A 2P 2x22= 44
7 RCCB of 25A 4P 3.9x7= 27
Power Dissipated by 1X40X5 BUSBARS - 49
"Power Dissipated by fuses, CTs,meters & auxilary relays(approximate)" - 21

The power dissipated by each of the installed components.
Pd= 52+32+41+114+81+1+44+36+49+21
Pd= 410 W

3. Characterisitcs of the environment air

Maximum Ambient Temperature Te max = 58 ºC
Minimum Ambient Temperature Te min = 20ºC
Average relative humidity RH = 100%


4. Average Desired internal temperature

They are defined by the nature of the components and characteristics of the environment air.

Maximum internal temperature Ts max = 60 ºC
Minimum internal Temperature Ts min = 25 ºC

5. Final tempeerature inside the enclosure with no thermal system

Maximum internal temperature: Ti max = Pd /(KxS)+ Te max


Maximum internal temperature: Ti max = 410/30.096 + 58
30.096

Maximum internal temperature: Ti max = 72 ºC


Minimum internal temperature: Ti min = Pd /(KxS) + Te min


Minimum internal temperature: Ti min = 410/30.096 + 20


Minimum internal temperature: Ti min = 34 ºC


K = 5.5 W/mý/§C for an enclosure made of Painted Sheet Steel

6. Determining the type of thermal device and its power : Psyst

If Ts min < Ti min No need for a thermal system

If Ts min > Ti min Need for Thermal System: resistant heater

If Ts max < Ti max Need for a Thermal system: Ventilation, fan, exchanger, cooling unit.

If Tsmax > Timax No Need for a thermal system; a circulation fan may be used to even out the temperature.

1. Permanent operation of the switchboard
Psyst = K x S (Ts min - Te min )-Pd
1. Discontinous operation of the switchboard
Psyst = K x S (Ts min - Te min )



7. Solutions with fans

The use of Fan and Grille is recommended
1 fans NSYCVF300M230PF +1 grids NSYCAG223LPF

Airflow Necessary 169.1712 m?/h
Airflow provided 260 m?/h( 1 fans)
Highest Temperature That the Enclosure will attain without cooling: > 55§C
(The EN60439 international standard recommends not to exceed 70øC)

Fan Characteristics
Dimensions 268 x 248 x 116 mm
Weight : 1.3 kg
Voltage : 230 V
Frequency (Hz) 50 Hz
Protection degree IP54
Function EXTERNAL FAN
Filter Filter included(Filter standard)
Electrical output (W) 36W/ 37W
Imax (mA) "0,171A/ 0,163A"

are there any errors in this calculation?

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Associate

Join Date: May 2011
Posts: 38
#1

Re: Errors In Heat Dissipation Calculation For An Enclosure

08/06/2011 11:07 AM

Dear friend ,

Your calculation steps are o.k , But what about the air flow ? How can you make assumption for the air flow mention 169.1712m3/h.Check this and do let us know for your clarification.

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Anonymous Poster #1
#4
In reply to #1

Re: Errors In Heat Dissipation Calculation For An Enclosure

08/07/2011 1:19 AM

Airflow Necessary= {Psyst / (Ts max - Te max)}x 3.1 meter cube/hr

where Psyst=Pd-K x S (Ts max - Te max)

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Guru

Join Date: Feb 2011
Posts: 1119
Good Answers: 11
#2

Re: Errors In Heat Dissipation Calculation For An Enclosure

08/06/2011 11:59 AM

There is an easy way of doing the computation by practical approach.

1) make a step by step trace of the process

a. heat dissipated from electrical component to air by natural convection at desired internal enclosure temperature. if Qec -heat dissipated by electrical component is greater than computed Qconv(enclosure) then typically you need air vent or air exchange on your enclosure. If Qcon>Qec you can probably let the enclosure closed unvented.

b. you can also direclty check conduction heat transfer of the enclosure from interal to external design temperature and assumptions. If your computed results from heat conduction is greater than Heat dessipated by electrical components convected to internal enlcosure space. You don't need air exchange anymore to enclosure, adding fan wont be necessary. Otherwise if its less than heat dessipated by components to internal space, either a fan should be employed or increase enclosure space to accomodate heat transfer that fits design parameters.

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Guru
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#3

Re: Errors In Heat Dissipation Calculation For An Enclosure

08/06/2011 3:11 PM

This sound more like a Mechanical Engineering problem and not Electrical.

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Guru

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#5
In reply to #3

Re: Errors In Heat Dissipation Calculation For An Enclosure

08/07/2011 2:36 AM

Yeah, this is a mechanical engineering problem. But it is of a class that is a frequent problem for electrical engineers.

Best book I ever saw on the subject is Dave S. Streinberg, "Cooling Techniques for Electronic Equipment". John Wiley& Sons, New York, 1980. ISBN 0-471-04403-2.

New editions available at $160-$220 from usual book sellers. Do a Google search and you can score a used textbook copy for as little as $13 plus $4 shipping.

Ed Weldon

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Participant

Join Date: Oct 2014
Posts: 3
#6

Re: Errors In Heat Dissipation Calculation For An Enclosure

10/09/2014 10:11 AM

Pfannenberg (www.pfannenbergusa.com) has a great heat load calculator for electrical enclosures on their website. You may find this useful to do some quick calculations.

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