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manojadat
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Join Date: Nov 2011
Posts: 3

Energy Meter

11/06/2011 8:54 PM

I have one ct energy meter having ratio 200/5 and the ct ratio is 100/5 what will be the multification factor
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wareagle
Guru
United States - Member - New Member

Join Date: Jun 2008
Location: Alabama
Posts: 1604
Good Answers: 63
#1

Re: Energy Meter

11/06/2011 9:10 PM

I do not understand your question but 200/5 = 40 and 100/5 = 20 as a multiplier.
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sriram1988
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Join Date: Sep 2011
Posts: 47
Good Answers: 2
#2

Re: Energy Meter

11/06/2011 9:27 PM

Answer is in the question itself.

i assume that your instrument will produce 5 amps in secondary,for maximum current in primary.

200/5=40 (M.F)

consider that your measure is 5 in secondary side ,then your primary current is

5 x 40 =200 amps

100/5 = 20 (M.F)
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msamad
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Join Date: Feb 2009
Location: Houston, USA
Posts: 946
Good Answers: 244
#3

Re: Energy Meter

11/06/2011 10:22 PM

See this link and you will find the answer.

http://cr4.globalspec.com/thread/36700/M-F-in-Electricity-bill (comment # 4)

From your question, I understood 200/5 is the CT ratio written on the meter dial but you are using the CT with ratio 100/5. The meter may have its own multiplying factor (M.F) written on the dial. If not, it is 1 (M.F = 1). In this situation, yours is the case 4, and the actual multiplying factor is M.F x (100/200) = 0.5 x M.F (i.e. half of the dial multiplying factor or simply half).

- MS

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 "All my technical advices in this forum must be consulted with and approved by a local registered professional engineer before implementation" - Mohammed Samad (Linkedin Profile: http://www.linkedin.com/in/msamad)
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manojadat
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Join Date: Nov 2011
Posts: 3
#4
In reply to #3

Re: Energy Meter

11/08/2011 7:45 PM

Thank u sir.. I think it is the answer i waiting for..
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