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Power-User

Join Date: Nov 2011
Posts: 258
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Vote for Me in This NASA CONTEST

07/09/2013 5:47 AM

I have participated in the Create the Future 2013 (it is an annual affair) contest conducted by NASA- which closed recently on 1st July. You will know more about the contest from http://contest.techbriefs.com/about.

My entry is on link http://contest.techbriefs.com/2013/entries/machinery-and-equipment/3827 Title is "ACHIEVE MORE THAN 85% EFFICIENCY WINDMILL".

I request everyone to kindly vote for me. I am willing to clarify- if anyone has doubts

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Guru

Join Date: Sep 2012
Location: Iowa, USA
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#1

Re: Vote for Me in This NASA CONTEST

07/09/2013 8:33 AM

I see no mention of a working prototype. You may on paper achieve 85% efficiency, but with a rotating "track" with wind blades, that goes through a momentum reversal. As well your drawing indicates a 90 degree wind direction forced change with a diverter, I doubt if this will work as expected. How much energy is lost with this, my guess is more then 15%.

Did you model all of this?

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Guru

Join Date: Apr 2011
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#2

Re: Vote for Me in This NASA CONTEST

07/09/2013 10:19 AM

'.....I am willing to clarify- if anyone has doubts....'

.

I have doubts. Please clarify.

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Guru

Join Date: Dec 2010
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#3
In reply to #2

Re: Vote for Me in This NASA CONTEST

07/09/2013 10:30 AM
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Guru

Join Date: Oct 2008
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#4

Re: Vote for Me in This NASA CONTEST

07/09/2013 2:55 PM

The two top figures are the same. Why put it in there twice?

Your "wind blocker director" will rob lots of energy from the wind stream, so using the "total of the area facing the wind" will give you grossly inaccurate wind power figures.

Finally, without knowing what the other contestants have offered, it would be disingenuous of us to vote for you simply because you are a forum member.

Good luck.

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Power-User

Join Date: Nov 2011
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#5
In reply to #4

Re: Vote for Me in This NASA CONTEST

07/10/2013 5:13 AM
  1. If you ask any Windmill expert the maximum efficiency achieved by windmills today is about 40% and most those installed around the world are just 15 to 20%.
  2. All experts have a wrong belief that no one can ever achieve more than 59.26% by any means.
  3. Now I am first stating that there are no such limits at all and ideally even 100% can be achieved. CR4 members who have responded so far have not looked at this crucial factor.
  4. Now let us assume that 15% losses will be there due to other factors as mentioned by Lyn, achieving 85% is also a great achievement- as I am breaking down that mental barrier of 59.26%.
  5. More than making a prototype - if I have got that mental block removed from the minds of experts- I will be satisfied.
  6. About wind blocker- I think it has been wrongly understood - I think. Let me try to sketch only the wind blocker alone below.
  7. Thank you for your good wishes

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Guru

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#6
In reply to #5

Re: Vote for Me in This NASA CONTEST

07/10/2013 3:32 PM

If you remove 100% of the net kinetic energy from air moving through your device, it would stop and clog your device....or other energy would have to be transfered to it to get it out of the way.

More importantly, what is you motivation to extract a greater percentage of the energy in the wind? Do you project 'wind fees' will be a major expense?

Lifetime cost/Kwhr is likely to be far more sensitive to construction/installation cost per expected lifetime Kwhr output, than energy extracted per total energy in the wind.

Out of curiousity, do you have any proof/argument/logic/reason behind your claim that Betz limit is erroneous?

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