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tienlongng
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Join Date: Sep 2013
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2D Beam Element, 4 Degrees Of Freedom

09/05/2013 10:18 AM

I went though a 2D beam element with two nodes and at each nodes there are 4 degrees of freedom: displacements (u1,u2) and its derivatives (u1' and u2'). I don't see what is the avantage of this element compared to the one with 3 degrees of freedom at each node: displacement(u1,u2) and the rotation (teta). Anyone knows the answer please help me? Thanks in advance
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CaptMoosie
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#1

Re: 2D Beam Element, 4 Degrees Of Freedom

09/06/2013 9:27 AM

Seriously? Time for you to head back to the classroom Laddie. And if this is being done on structural Finite Element Modeling software, you need to read the directions.

Just saying, learn the basics!

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tienlongng
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#2
In reply to #1

Re: 2D Beam Element, 4 Degrees Of Freedom

09/06/2013 10:34 AM

Thank you for your answer. But I don't know if my question is clear.

I read something about it. They said if you consider the dispalcement of the share and the bending seperatly in high order beam, you need to introduce another degree of freedom with a cubic displacement function assumed for both the bending and the shear deformation instead of having three degree of freedom when you relate the share and the bending displacement.

It's that what you think also? It's what I know about it but if you know other things related to this issue please let me hear from you.

Thank you
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