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Electrical Engineering

10/16/2014 1:40 AM

what is the formulae to calculate the KWH [kilo watt hour] in three phase power supply to a motor of 50 hp 415 volts 50 hz. power factor is 0.9

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#1

Re: ELECTRICAL ENGINEERING

10/16/2014 1:44 AM

KW= (volts x amps x power factor x 1.732) divided by 1,000

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#2
In reply to #1

Re: ELECTRICAL ENGINEERING

10/16/2014 2:21 AM

And?

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#4
In reply to #2

Re: ELECTRICAL ENGINEERING

10/16/2014 12:35 PM

X hours of operation, which should be obvious.

Oh wait, the answer to the entire QUESTION should be obvious... derr.

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#5
In reply to #4

Re: ELECTRICAL ENGINEERING

10/16/2014 11:58 PM

Rated kwh

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#7
In reply to #4

Re: ELECTRICAL ENGINEERING

10/17/2014 12:14 AM

That was an easy homework question. Do they get any harder?

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#8
In reply to #7

Re: ELECTRICAL ENGINEERING

10/17/2014 12:27 AM

What... is the air-speed velocity of an unladen swallow?

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#9
In reply to #8

Re: ELECTRICAL ENGINEERING

10/17/2014 12:36 AM

African or European?

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#10
In reply to #9

Re: ELECTRICAL ENGINEERING

10/17/2014 12:40 AM

Umm, I - don't know that ----Auuuuuuuuuuugh

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#3

Re: ELECTRICAL ENGINEERING

10/16/2014 7:00 AM

It's the actual motor output (shaft) power in kW (which may be less than the rated power), divided by motor efficiency times hours run.

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#6
In reply to #3

Re: ELECTRICAL ENGINEERING

10/16/2014 11:59 PM

Actual kwh

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#11

Re: Electrical Engineering

10/17/2014 3:25 AM

KW= {(VOLTS(avg) x AMPS(avg) x p.f x 1.732)} / 1,000

please use 480V in the formula

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#12
In reply to #11

Re: Electrical Engineering

10/17/2014 7:29 AM

Why 480V? He said 415V.

It should be RMS volts and amps. Average for a sinusoidal wave is zero.

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#13

Re: Electrical Engineering

10/17/2014 9:32 AM

Whatever the power company says it is. -- JHF

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