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Commentator

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HERTZ Stresses

10/08/2015 6:52 AM

I happen to see a report in which the state of stress on both the parts in contact show the same pattern, including the depth of maximum shear stress and its numerical value. one of the components is a ball/roller and the other one is a flat plate. I sincerely feel the extra quantum of material present in the plate would surely reduce the stress values. can anyone throw some light on this? Thanks.

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#1

Re: HERTZ stresses

10/08/2015 8:01 AM

Not without seeing your report. Is there anything specific you don't understand? If so, then you could post that and see what others have to say about it.

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#3
In reply to #1

Re: HERTZ stresses

10/08/2015 8:23 AM

My guess is that the area of contact is much smaller than the dimensions of the ball or plate so the resulting stress would be virtually identical.

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#5
In reply to #1

Re: HERTZ stresses

10/08/2015 9:29 AM

I am herewith sharing the image. My question is that why the ball with 50 mm radius

material curve and, the flat plate with bulk of material being available adjacent to the

induced stresses to share the load, see the same stress values beneath the point of contact?

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#6
In reply to #5

Re: HERTZ stresses

10/08/2015 10:01 AM

Because the surface area where the ball contacts the plate maintains a consistent size therefore both surfaces experience the same loading and share the same stress moments.

Whatever load and movement that is applied to the ball is immediately transferred directly to the plate surface.

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#2

Re: HERTZ stresses

10/08/2015 8:16 AM

Reducing stress could be achieved by, well, reducing the stress.

Lighten the load.

Spread it out so the burden is shared through larger and or more numerous supporting components.

If the path is regular consider contouring the plate to make the contact patch with the ball larger.

.

It also would help if you provided more details and a better explanation.

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#4

Re: HERTZ stresses

10/08/2015 8:45 AM

Stress is not defined by the geometry if it refers to the strength of the material.

Same material same stress.

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#7
In reply to #4

Re: HERTZ stresses

10/08/2015 10:48 AM

Stress = (Force/Area) so geometry does have a role in defining the area the force is applied over.

Ultimate and Yield stress are material properties but when calculating a given stress for a given load the geometry does need to be considered a factor.

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#8
In reply to #4

Re: HERTZ stresses

10/08/2015 1:10 PM

In above sketch you see two situations: -left-before applying a load on the ball and -right- with load on.First you should understand that those deformations are very low as amplitude and LOCAL. Both surfaces will deform under load, the red area shows how the plane will deform and the green the ball deformation. The thick black line shows the contact surface after loading. The dotted lines show the surfaces before loading.On every point of contact area stresses MUST be equal for the equilibrium of the surfaces. If you look at the graphs you see how fast the stresses decrease with the depth. This mans that the material which is "behind" the surface layer does not play an important role in the distribution of contact stresses.Hertz equations were determined taking into consideration the two local deformations.As you will note the maximal deformation is in the enter thus the maximal stress will occur at this point.This sketch shows also why the stress distribution is parabolic. Hertz applied the equations of the elasticity theory in order to obtain his characteristic equations for the contact. It must be said that because of different approximations his equations are not valid if the two curvatures are too near to each other.

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#9
In reply to #8

Re: HERTZ stresses

10/09/2015 12:50 AM

Thank you Guru Nick for the answer with an appropriate illustration. From the formulations, the variables that contribute to the stress variation beneath the surface of contact appear to be Modulus of Elasticity and the poisson's ratio of the materails of concern. The geometries of the components along with the above two factors do only govern the peak compressive stress at the contact. I need to corroborate your last statement that when both the geometries are closely conforming may be in all the directions, the problem would simply degenerate to a compressive case rather than a contact stress case and in which these formulations would give spurious results.

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