Previous in Forum: PC Problems with Standby Mode   Next in Forum: Electronics - Cordless Control System
Close
Close
Close
11 comments
Rate Comments: Nested
Associate

Join Date: Sep 2006
Posts: 31

RC circuit

08/16/2007 3:24 PM

Hi all

I am a mechanical engineer, and i was dealing with a an analogue AC signal from a tranceduser, I wanted to transform the signal into DC to be taken on a computer. I used a full wave rectyring bridge then I used a capacitor to smoothen the wave. I know that there is time constant that must be calculated t=RC, so I used a 10 microfarrad capacitor which gave good results we some variations, I wanted to use a very large capacitance to avoid these peaks and valleys, but the results were not logic at all, and the voltage was just moving down by the time and I did not know why!

So would any body can explain why that happened, and what is the wrong of using very large capacitance 470 microfarrad?

thanks a lot

Register to Reply
Interested in this topic? By joining CR4 you can "subscribe" to
this discussion and receive notification when new comments are added.
Power-User
Technical Fields - Education - New Member Technical Fields - Technical Writing - New Member

Join Date: Sep 2006
Posts: 367
Good Answers: 1
#1

Re: RC circuit

08/17/2007 4:14 AM

Not enough info.

Can you show the diagram?

Register to Reply
Associate

Join Date: Sep 2006
Posts: 31
#2

Re: RC circuit

08/17/2007 5:47 AM

This the signal taken from the full wave rectifier bridge

Here i USED a 10 mico farrad capacitor

Here I used a 470 microfarrad capacitor

I need to remove the ripples from the second figure?

I do not know why the voltage on the 470 microfarrad capacitor kept increasing?

Register to Reply
Guru
Popular Science - Weaponology - New Member United Kingdom - Member - New Member

Join Date: May 2007
Location: Harlow England
Posts: 16512
Good Answers: 670
#3
In reply to #2

Re: RC circuit

08/17/2007 8:17 AM

The trace with the 10UF looks about right for basic smoothing...

You probably need a o.1uF cramic to get rid the high frequency noise...maybe a few turns of wire through a small ferrite core would help too (after the 0.1uF)

If this is going into a computer input of some sort...let the software do the smoothing/averaging/processing.

(I reserve the right to be wrong, or of no help what so ever)

__________________
health warning: These posts may contain traces of nut.
Register to Reply
Power-User

Join Date: Mar 2006
Location: Valdosta, GA
Posts: 361
Good Answers: 8
#4
In reply to #2

Re: RC circuit

08/17/2007 8:43 PM

The 470 mfd capacitor was increasing because it was charging up. It takes a lot longer than the smaller capacitor to reach full capacity.

__________________
Always use protection.
Register to Reply
Power-User

Join Date: Mar 2006
Location: Valdosta, GA
Posts: 361
Good Answers: 8
#5

Re: RC circuit

08/17/2007 9:01 PM

The 470 mfd capacitor is a poor choice simply because of it's capacitance. It will charge up and try to maintain a voltage that is probably close to the RMS or maybe even close to peak voltage if there is sufficient current which I doubt is the case with a transdeucer. I am assuming that you want to preserve the count coming from the transdeucer in the form of a signal that is more like a digital on/off signal? In that case, you may need to use an OPAMP circuit with a threshold around 4 volts if I am reading your diagram correctly. You still may have to play around with the capacitance across the signal coming from the bridge rectifier some unless some of you math guys have a formula for that?

__________________
Always use protection.
Register to Reply
Associate

Join Date: Dec 2006
Location: Jonkoping in Sweden
Posts: 33
#6

Re: RC circuit

08/19/2007 2:46 PM

Maybe it is not the best way to rectify the signal, but I don´t know yet. Can you tell me, where is the information in the signal, in the amplitude or in the frequency? Which is frequency coming from the transducer?

Anders G

Register to Reply
Anonymous Poster
#7

Re: RC circuit

08/21/2007 12:39 AM

hi,

dear you just calculate the current which is going inside the load after that apply a capacitor on its terminals. the factor for converting the AC into DC.you may also use this fenomenon with a circuit containing OP-AMP. I can give you the exact solution if you will provide me the circuit by email my email is i.sanjai@gmail.com

take actions on your circuit.

Register to Reply
Associate

Join Date: Sep 2006
Posts: 31
#8

Re: RC circuit

08/25/2007 4:08 AM

Dear all

thanks a lot for your concern, your replys made me know more about the problem,

i want to say that this signal is coming from a load cell which is a prove ring type. The output voltage increases with increasing the tension force. I think it is working with the concept of inductance. A metallic strip cuts a magnetic field which is produced in some coils from a 220AC voltage. The output is a about 2AC volts at no load and it increases by increasing the force.

This curve was taken by a 10 microF capacitor. Actually it is great but i need to remove the ripples in the right half (the line needs to be thinner)

Register to Reply
Guru
Popular Science - Weaponology - New Member United Kingdom - Member - New Member

Join Date: May 2007
Location: Harlow England
Posts: 16512
Good Answers: 670
#9
In reply to #8

Re: RC circuit

08/25/2007 4:29 AM

That looks fine ...see #3 !

__________________
health warning: These posts may contain traces of nut.
Register to Reply
Associate

Join Date: Sep 2006
Posts: 31
#10

Re: RC circuit

08/25/2007 4:39 AM

thanks DEL

there is no problem about the 0.1 ceramic capacitor, but can you tell me more how can i connect this core and winding?

Register to Reply
Guru
Popular Science - Weaponology - New Member United Kingdom - Member - New Member

Join Date: May 2007
Location: Harlow England
Posts: 16512
Good Answers: 670
#11
In reply to #10

Re: RC circuit

08/25/2007 6:12 AM

Try any ferrite bead or small inductor (RF supressor) in series with the signal.

e.g.

1. Assume your 0v, earth,gnd or whatever you want to call it goes straight through to your input.

2. The Signal wire should have the 0.1uF down to the 0v/gnd then the go through the inductor (ferrite bead whatever). Then the big 10uF between signal and 0v/gnd.

The idea (don't shoot me anyone unless you can give a better explanation.) is the high frequency noise will go through the 0.1uf to ground (low impedance) rather than through the inductor (high impedance).

I don't promise it will help but a bit of tinkering about with screened leads, ferrite beads and 0.01 or 0.1 uF will usually quieten things down a bit! If you havn't got screened leads then at least twist the wires together.

__________________
health warning: These posts may contain traces of nut.
Register to Reply
Register to Reply 11 comments
Copy to Clipboard

Users who posted comments:

Anonymous Poster (1); Gustav180 (1); Keywalker (2); kik0kik0 (3); southern123 (1); user-deleted-1105 (3)

Previous in Forum: PC Problems with Standby Mode   Next in Forum: Electronics - Cordless Control System

Advertisement