Free Body Diagram - Vice Grip Plier

I don't understand why my thread was deleted so I' posting it again.
I ran into a few problems when solving the statics equations of the free body Diagram of these pliers:

A worker uses these pliers and applies 200 N on it to crush a hex nut. Very basic stuff, the worker does not apply torsion yet. I just want to make sure the diagram is correct.

So I broke it up into the following pieces:
It's modelled on solid works , so i measured everything there(i double checked the measurements).

I ran these equations on MAPLE and this is what I got:

P1 = 200 (N)

∑1Fx = bx - c*cos(α) = 0

∑1Fy = by + P1 - c*sin(α) = 0

∑1MB = by + P1*LBDx - c*sin(α) = 0 # LBDx= lenght from B to D on the x axis

bx= 403.247 by= 347.746 c= 680.173

∑2F = c - h = 0

h=680.173

∑3F = e - f = 0

∑4Fx = -bx + e*cos(γ) + ax + g*sin(20.4) = 0

∑4Fy = - by + ay + e*sin(γ) - g*cos(20.4) = 0

∑4MA = g*sin(20.4)*LAG1y +g*cos(20.4)*LAG1x +e*sin(γ)*LAEx +e*cos(γ)*LAEy-by*LABx -bx*LABy = 0

∑5Fx = -ax + f*cos(γ) + h*cos(α) - g*sin(20.4) = 0

∑5Fy = -ay - f*sin(γ) + h*sin(α) + g*cos(20.4)-P2 = 0

∑5MA = -g*sin(20.4)*LAG2y - g*cos(20.4)*LAG2x - f*cos(γ)*LAFy - f*sin(γ)*LAFx + h*sin(α)*LAFx - h*sin(α)*LAHy - P2*LP2 = 0

F = 1952.786 P2 = 200 , ax = 5338.525 ay= 4413.985

e = -6044.681 f = - 6044.681

The equations turned out fine and balanced, but the results seem a bit too high , and further more , the spring should be in compression and not in tension as demonstrated by the final result of e and f.

I don't understand what I'am doing wrong , but the error seems to be in the last 6 equations if anyone is willing to help me I would mighty appreciate it! Any suggestion is welcomed.
Thank you soo much for reading!