The optimization of overcurrent protection for a 4200 kW wound induction motor, which drives a raw mill in a cement plant, is under review. The motor specifications are: 4200 kW, 6.3 kV, 471 Amp, 994 RPM. The objective is to ensure the motor trips at 100% load with a delay of 10 seconds. Additionally, a 1400 kVar capacitor bank is integrated with the motor.
Simulation results from ETAP have revealed the following:
- At the MV motor protection relay and energy meter, the current is 114 Amp with a power factor of 96%.
- At the motor terminal, the current is 471 Amp with a power factor of 85%.
It appears that the capacitor bank, positioned between the motor terminals and the MV feeder output, is influencing the current readings. The capacitor bank supplies part of the current, leading to a noticeable discrepancy between the current measured at the relay/energy meter and at the motor terminal.
Given this configuration, it is proposed that the reference for overload protection (I>) for the relay should be adjusted to 414 Amp. This adjustment takes into account the current supplied by the capacitor bank, as indicated by the ETAP simulation results. Therefore, 414 Amp should be considered the 100% load current for relay, instead of 471 Amp ( mentioned at motor nameplate ).
Feedback and insights from the forum on this approach would be highly valued, particularly regarding the accuracy of using 414 Amp as the reference for overcurrent protection in this scenario.
Thank you!

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