For my aerospace application I need very large vacuum chambers but at light weight. I had thought that the chambers could be made lightweight because the formulas for the thickness of a vacuum chamber would be almost the same as the formulas for the thickness of a pressure chamber (containing high pressure within.) The only difference I thought would be you would use the strength in compression of the material in the formula rather than the strength in tension. But then the formula for a pressure vessel says that the thickness to size ratio equals the inner pressure to be contained to the materials tensional strength ratio. So if your material had a tensional strength of 10,000 bar, within the range of common materials, and the pressure inside was only 1 bar higher than the outside, your pressure vessel would only have to be 1/10,000th as thick as it is wide. So a 100 meter wide pressure vessel would only have to be 1 cm thick. So I thought that vacuum vessels would be analogous. So if the *compressional* strength was 10,000 bar you would likewise need a 1/10,000th as thick a wall as the vessel diameter for the pressure 1 bar on the outside and 0 bar on the inside. However, I found that the engineering for vacuum vessels is more complicated than this. (For instance, try to find a single formula for the thickness of a vacuum vessel on the web!) A key problem for such vessels is actually buckling of the structure. From looking at various examples made from steel, an approximate rule of thumb is that you need a thickness of 1/100th that of the diameter of the vessel. So for a shroud 100 meter across you would need a thickness of 1 meter. This would result in a prohibitive mass for the chamber for my application. So to get the thickness back to as low as it is for pressure vessels why not turn it into a problem in tension? I'm suggesting making the chamber walls of a high tensional strength material (or fabric) stretched over a frame. This is how I'm envisioning it:
Hyperboloid of one sheet.
http://www.math.umn.edu/~rogness/quadrics/hyper1.shtml
There would be a sheet reaching from a high strength ring at the top to one at the bottom. Then the resistance to the outside pressure will be provided by the material in *tension*. As for buckling, the shape is already "buckled": the situation is analogous to that of the strength provided by a pyramid for a tall structure. It is the shape for maximal strength under compressional pressure of its own weight since that is the shape a structure will naturally fall into if it collapsed.
I don't know that the hyperboloid is the shape of maximal tensional strength against buckling but I imagine it is similar. You would also need to calculate how far apart you would keep the rings to support the hyperboloid sheet to have maximal strength at the lowest weight.
I don't know the formula for calculating the thickness of the hyperboloid so I'll look at a simpler case. Imagine a frame in the shape of a vertical rectangular box, i.e., the edges only, no faces. On each vertical open face imagine a cylindrical surface, caved inward.
The 1 bar outside pressure would be supported by these cylindrical surfaces. Then the thickness should be the same as the thickness of a cylindrical pressure vessel, with the pressure supported in tension. So a 10,000 bar tensional strength material at 100 meters across would require a 1 cm thickness.
For the actual shape of maximal strength, perhaps the hyperboloid, the thickness would be even lower.
Any comments on the validity of this argument for creating high strength vacuum chambers from the walls being in tension?
Bob Clark
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