Previous in Forum: Should I manufacture Mechanical Power Presses or Hydraulic Power Presses   Next in Forum: Could we just circulate the air in scramjet propulsion?
Close
Close
Close
10 comments
Rate Comments: Nested
Participant

Join Date: Mar 2008
Posts: 2

Time to heat/cool

03/08/2008 10:53 AM

Practicing some thermo problems and was wondering the method... or best guess way of determing time to heat/cool and power if only given mass of objects, initial and final temps or time, temp and amount of heat removed.

Examples of problems in which I'd like to calculate the time -

50 lb ice at 25F and 300 BTU removed? How long does it take to get to final temp?

600 kg of water at 90C is mixed/poured into 200g metal pot. How long to get to final temp?

2 lb of water at 100F is added to 5 lb at 50F how long to get to final temp?

5 kg iron bar put into 10 kg of water. Water temp to raise from 20 to 30 C. How long to get to the temp?

All these involve straightforward ways of finding the temp but how to find the time?

Thanks.

Register to Reply
Pathfinder Tags: time heat temp
Interested in this topic? By joining CR4 you can "subscribe" to
this discussion and receive notification when new comments are added.
Power-User

Join Date: Apr 2007
Posts: 414
Good Answers: 19
#1

Re: Time to heat/cool

03/09/2008 1:43 AM

You don't need to guess, but you do need more information than is supplied here. Since heat is electromagnetic energy, its rate of travel is at a maximum in a vacuum, and less traveling through other substances. The rate of heat transfer depends on the temperature differential of the objects involved, as well as their area of contact and their ability to conduct heat.

The simplest case simply assumes that those objects are in such intimate contact that the heat transfer is essentially instantaneous. In the real world it seldom is. Thermodynamics is a fascinating topic, and extremely useful, but the resources of this forum are for the most part not equal to offering a semester's knowledge in a paragraph or two.

Register to Reply
Guru
Hobbies - DIY Welding - New Member

Join Date: Sep 2007
Posts: 1601
Good Answers: 58
#2

Re: Time to heat/cool

03/09/2008 9:06 AM

The answer to your question involves the the term "thermal time constant". You can look it up in any text on heat transfer, or get a good feel for it from wikipedia, or Google. It's a little too involved to explain in detail here, but it's not a vey complicated concept.

Register to Reply
Guru

Join Date: Mar 2007
Location: City of Light
Posts: 3943
Good Answers: 183
#3

Re: Time to heat/cool

03/09/2008 11:14 AM

If the text is not easy to read I am sorry but it is all i could do. If you want to have a better look then send your e-mail address and i shall send you it in .doc format. As one of the commentators wrote it is simple but you cannot find it every where. I hope it is clear but if you have still questions please ask. The assumption of "instantaneous" transfer is totally out of question since heat is traveling at a speed which depends on material properties and i dare say that assuming it with "light speed" is a very big error or at least a too simplistic simplification. To make it clear the above equations could be a good approximation for a piece of metal in water but are far from reality for a piece of stone in a heavy oil. Even in the case of metals there are big differences between difusibility values so that a cooper piece will be more homogen in temperature than a piece of stainless steel. For steels the best example of difusibility limitations is the quenching test "jominy". If the speed of heat transfer would be so big as assumed the hardness will not depend on the distance to the cooled surface since the temperature change would be every where the same. A simplified model has never the less be respectful of physics.

Register to Reply
Guru
Engineering Fields - Retired Engineers / Mentors - New Member

Join Date: Dec 2006
Location: Brecksville, OH
Posts: 1621
Good Answers: 18
#4

Re: Time to heat/cool

03/09/2008 6:12 PM

Heat transfer rates and equilbration times are the subject of kinetics rather than Thermodynamics. Factors such as surface areas available for transfer of heat are controlling rather than the basic masses of the materials involved in the transfer.

__________________
"Consensus Science got us into this mess, then why can't it get us out?" : Rephrase of Will Rogers Comment
Register to Reply
Associate

Join Date: Dec 2007
Location: South Africa, Jhb
Posts: 28
Good Answers: 2
#5

Re: Time to heat/cool

03/10/2008 3:28 AM

Search on google and get your units, juggle the equation to get what you need.

watts =

mass (kgs) x Specific Heat Capacity (K cal Kg deg C) x Temp difference

860 x Heat Up Time (hours)

NB dont forget that you must add in the primary or secondary item to be heated, eg. 600Kg of water and the 200grm pot to get a correct wattage.

Seems like these are exam/test questions...

__________________
Insanity is not running into a brick wall over and over again. Insanity is expecting a different result each time.
Register to Reply
Participant

Join Date: Mar 2008
Posts: 2
#6
In reply to #5

Re: Time to heat/cool

03/11/2008 1:25 AM

What I am doing is going over some basic questions in preparing to study for the PE. I started thinking what basic assumptions are to made or formulas/theories to apply to get the times for the heating.

These aren't "involved" questions, as the temp answers are very easy, nor are they homework questions, just "would like to know if" questions. Practical/"simple" solutions are sought no second semester thermo or heat transfer course lecture is requested.

More on line of "on the back of a napkin" formulas.

Thanks for the help/guidance.

Register to Reply
Guru
Hobbies - DIY Welding - New Member

Join Date: Sep 2007
Posts: 1601
Good Answers: 58
#7
In reply to #6

Re: Time to heat/cool

03/11/2008 9:00 AM

The formula should be the same on either side of the napkin. The most important thing to remember is that the temperature change with time will not be linear. It will be exponential and will involve the natural logarithm to the power of -t/rc where t is time, r is thermal resistance, and c is heat storage capacity. The product rc is called the thermal time constant. It is the same equation that applies in electrical engineering to the electrical current versus time when discharging a capacitor through a resistor. The equation is very common in almost all branches of engineering, and you should become familiar with it.

Register to Reply
Anonymous Poster
#8
In reply to #7

Re: Time to heat/cool

03/11/2008 9:54 AM

I would like to know if, when writing your comment, you had a look at#3

Register to Reply
Guru
Hobbies - DIY Welding - New Member

Join Date: Sep 2007
Posts: 1601
Good Answers: 58
#9
In reply to #8

Re: Time to heat/cool

03/11/2008 11:58 AM

Answer #2 spoke of the term "thermal time constant". Answer #3 gave a more complete description but was not very legible on my monitor. Answer #7 described the basic math used to calculate thermal time constant. If one remembers nothing else, one should remember that after one time constant, (RC), the temperature, voltage, or whatever parameter you are dealing with, will have changed close to 63.2% of its steady state change.

Register to Reply
Anonymous Poster
#10
In reply to #7

Re: Time to heat/cool

03/11/2008 7:04 PM

the natural logarithm to the power of -t/rc

logarithm is the power of a base to obtain a value in the case you discuss the base "e" is at the power -t/rc i.e. the last is the logarithm and is not at a power.

as an example: log(1000)in the basis 10 is 3 because 1000 = 10^3

Register to Reply
Register to Reply 10 comments
Copy to Clipboard

Users who posted comments:

agua_doc (1); Anonymous Poster (2); bubbapebi (1); NewEng2008 (1); nick name (1); Ryan (1); welderman (3)

Previous in Forum: Should I manufacture Mechanical Power Presses or Hydraulic Power Presses   Next in Forum: Could we just circulate the air in scramjet propulsion?

Advertisement