A guy wants to build a house on the side of a hill. The County wants a "Draining and Grading Plan". I imagine this is a plan is to show any rainwater runoff will be shed around the house, and not flood the house. So, you need to show your swale or ditch is deep enough and wide enough to handle the expected deluge of that worst storm in 20 years, and direct the water around the house, and down the hill, towards a culvert under the road.
So, I guess you measure the land above the house to get an idea of the expected area of the "watershed". Then assume a storm water rate of say, 1" per hour. For example, if the area measured 1 acre, or 43,560 sf, you'd have a volume of 3630 cf/h to get rid of. Assuming you could direct half around each side of the house, your swale would have to be large enough to carry 1815 cf/h, or 30 cf/m, or 0.5 cf/s. If your swale cross section was a triangle, 4 ft across and 1 ft deep, it'd have an area of 2 sf; which would produce a velocity of 0.25 ft/sec. Which is probably an acceptable rate, but what standard rate governs this?
For the remaining area of the lot, I would imagine you'd show the slope 1/4"/ft away from the house, and towards the swales, and towards the downhill edge of the lot. If the house walls were to be of standard 2x4 wood construction, the plan could include constructing a "stem wall" of masonry about 2 feet high, upon which the 2x4 walls would be installed; and maybe applying waterproofing to the outside of the stem wall, up to about 6" above finish grade.
How does this sound? Thx.
Good Answers: