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I assume that you must mean how much of the pumps energy goes into heating the liquid when you pump it?
For example C2 at -42.2 F and 200 psia will be -35.5 F at 600 psia through a pump with an isentropic efficiency of 70% or:
C2 at -42.2 F and 200 psia will be -34.6F at 2000 psia through a pump with an isentropic efficiency of 60%.
You find the ethalphy at the begining P&T and find the enthapy at the ending P at a CONSTANT entropy. Subtract the two and thats the work that must be done to pump the fluid @100% efficiency. assume 100 BTU/lb is the difference.
Now, if the efficiency is 70%, the pump will need to be the enthalphy require in the step above dived by the efficiency. so 100/.7 = 142.5 BTU/lb.
Go back and add 142.5 btu/lb to the starting ethanphy at your T&P. Then look up at what temperature does this enthalpy match with the outlet pressure.
Take the temp before it is pumped and after then subtrasct. You let out too much stuff from your question. Is there a filter which will cause back pressure on a pump? and other things.
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