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Member

Join Date: Mar 2008
Posts: 8

Heating Load

08/05/2008 1:26 PM

How do I calculate the electrical coil load requirement to raise the temperature of a 16 oz. sample of water 100 deg.F in one minute?

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Guru

Join Date: Aug 2006
Posts: 4484
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#1

Re: Heating Load

08/05/2008 4:22 PM

Personally, I pick whatever measuring system makes the calculation easier. I'll let you look up the conversions, but we could call 16 oz half a liter, and 100 degrees f is 55 degrees C. So, without having to use a calculator, you can say that 500 grams of water would require 27500 calories to add 55 degrees. That's about 32 watt-hours, or roughly 1900 watt minutes.

Electric heating elements are considered 100 percent efficient -- in other words, there is no "waste" heat. However, if you we are using an immersion heater in a pan of water, you'd have heat losses to the environment. In a well-insulated system, such as a water heater, the actual efficiency can be over 90% (and this depends strongly on how efficiency is measured: If you input the heat, turn off the power, and then come back in a week to check the temp rise, you will find the tank cold).

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Associate

Join Date: Jul 2008
Location: Red River Valley
Posts: 35
Good Answers: 1
#2
In reply to #1

Re: Heating Load

08/07/2008 2:49 PM

Ken - It seems to me that when I was in a place where temperature was read

in Celcius, 100F was about 38 C. (or 37.788C) .. Regards Ol' timer.

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