Pump energy consumption

Hello

The adsorbed power P ( power input ) is the power input at the coupling or pump shaft. If is higher than the hydraulic power Pu output by the amount of the pump losses.

If the efficiency η of the pump, which reflects the pump losses, is known, the absorbed power of the pump can be calculated from the following ecuation:

P=Pu/η= ρ·Q·H/367·η in kW with ρ in kg/dm³, Q in m³/h and H in m, η is expressed as a decimal value.

So we have

H= toatal head of the pump

Q= pump flowrate

ρ= fkuid density

η= effiency

Hope this hepls

hi: i am shankar from india.

the formula for calculating bkw(brake kilowatts) for a particular discharge and head is as follows:

bkw= (q x h)/102 where q is discharge in litres per second and h = head in metres

translating 600 cmtr per hour to litres per second will be 111

bkw = (111 x 600)/ 102 = 652. 94 for pump efficiency of 100%

pumps run between 60 upto 95% efficiency

if your pump has an effciency of 80%, power of the driver needed is 652/0.8,

which will be 815 kilowatts. Your driver will be of power nearest to this.