Specific Heat capacity

If you post the rest of your homework we could work on it all at the same time.

Home works are done to make the student think We are willing to help when he made his work but has difficulties. So 1st step you try to solve and 2nd step present your results for a check.

Do NOT expect us to make your work.

I'll give you a few hints, but as the guru says, won't solve it for you.

Break up the problem into parts

1. Write down your variables (ie m(iron)=980g )

2. Use the formula q=m*C*(delta)T where q=heat, m=mass, C=specific heat, and (delta)T is the change in degrees C twice, once for water and once for the iron, and add them to find out how much total heat energy you need to change the water from 25C to 100C.

3. Use hints from the UNITS to answer the final question. You should now have the amount of heat energy needed in Joules and you already have a rate that the energy is being fed into the system given to you in Joules per second (475 J/s). What do you need to do to the numbers to get seconds on top? (HINT: it involves division). Good Luck.

Presumably the system is adiabatic and no heat is lost from the pan and water? That would make the problem much more difficult.

If so they should explicitly say that there's no heat transferred out of the system.

I don't see the need to use iron's variable for the answer with above assumptions. Basically, it is a two steps question.