Motor nameplate power

This is in fact the same question that I posted today with the title "How to Calculate Motor Full Load Current". I appreciate the reply to it.

Thanks,

- MS

The value on the nameplate is Output (mechanical) power. To get input (electrical) power, you take the nameplate power divided by the efficiency and power factor at any given load point.

Thank you

Of course as I have pointed in earlier posts also people simply are rabid to search-engines . I am not, and just to check up the efficacy, for the nth time ,I ran the simplest query "Motor name plate IEC"

http://www.google.co.in/search?hl=en&q=motor%2Bname%2Bplate%2BIEC&meta=

Results 1 - 10 of about 340,000 for motor+name+plate+IEC. (0.17 seconds)

and specifically the first link on the query was -

http://ecmweb.com/mag/electric_understanding_induction_motor/

Rated horsepower — Horsepower is the measure of how much work a motor can be expected to do. This value is based on the motor's full-load torque and full-load speed ratings and is calculated as follows:

Horsepower (hp)=[Motor Speed×Torque (lb-ft)]÷5,250

The standardized NEMA table of motor horsepower ratings runs from 1 hp to 450 hp. If a load's actual horsepower requirement falls between two standard horsepower ratings, you should generally select the larger size motor for your application.

I assume the torque is an output quantity (mechanical ?)

This type of silly questions (with due regards) need be asked ?

"This type of silly questions (with due regards) need be asked ?"

With all due regards, need they be answered?

Yes, agreed. In future i will avoid asking this type of questions.

Dear Lspraba,

Don't be so easily intimidated. Remember that some of the most profound inventions and ideas resulted from a 'silly' question from a small child.

We at CR4 get to remember that our experience came from being inexperienced and asking 'silly' questions.

Regards, CJM

It is the maximum output power that the motor can provide without risk of damage. The mechanical load will determine the instantaneous actual power, which should be always less than the maximum power rating for the motor overload protection not to operate.