Air Hammer Force

To a first approximation, the force will be (cylinder diameter) * (gauge pressure), so that's pi x (0.75/2)² x 90 ≈ 12½ lbf at the top end.

Thanks for the response.

I believe my next problem is determening the velocity of the blow to get the full impact force. e.g. the multipliler to the 12 1/2 lbf.

Getting out of my field - but you would need to know the mass of the piston + rod + head (i.e. the moving bits). These would be accelerated by the 12½ lbf for the length of the stroke, reaching max. speed (& therefore having max. kinetic energy) just at the end of the stroke.

Anyone out there know any more about it? Help!

if the supply was a constant 90 psi that's correct , if the pneumatic supply fluctuates within the range of the pressure settings.. the the applied force would be variable in proportion to the available pressure at the instant the air tool trigger is pulled..if this process is on a moving belt.. and many air hammers are triggered at once the psi drop could be all the way to 60 psi..if i was manufacturing , and i knew that sometimes the " male part" was inserted with 60 lbs.. and others , with up to 90 psi.. i'd be a little concerned with quality control. .if you've ever held the air tool in your hand ,, watched the pressure drop as you pull the trigger...

In this case the tool will be handheld and operator will go by sight to verify piece is fully inserted. E.g. a 1.5 inch wide 9/16 piece thick (tapered) 8 ft long piece first set into he receiving piece then inserted up to a stop inherent in the geometry of the two pieces. e.g. an L shaped piece being inserted up to the 90 degree point.

from my limited manufacturing process knowledge, why are you trying to force the piece into the orifice?... the potential to damage the land of the orifice or the gland of the " male part" is extreme..wouldn't pressing the piece into place be the optimum choice ?

Pressing in the piece was first choice but proximity, orientation, configuration and size of cylinder needed for 400 lbs insertion force made the task much to complicated - and exspensive. At this point this is just an idea. I will experiment with several set ups to determine real outcome and any damage caused to either part. The block for inserting the piece is a material that will not mar the pieces when struck with a hammer.

i think you mentioned a jig.. im new here .. so i don't know how to use all the tools .. ie insert a sketch..but..here goes..if the jig was a close tolerence fit..and the insertion path was " spot on ".i would rather slow the belt speed down to insure a complete seating of my male part..especially if im using " o-rings " in this ....the block may not mar.. but will the flange supporting the orifice stand up to a sudden vicious ping?..

hey good luck...

i see , now..i might verify that the hole is reamed to the angle of the tapered insert..to facilitate acceptence of the rod.. placining a " backing plate" over the exposed end.. love tapping it into place, & i'd do it wet..hope this is helpful..good luck

Don't forget the safety aspect of Newton's 3rd law. You will probably have to rotate operators through that portion of the operation. Operating an air hammer/chisel for long periods of time can wear a person down pretty quick.

I found that out breaking up rocks to put a waterfall in the back yard.

and they size dosent matter

If interested, we have the capability to provide this service to you.

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Thanks

Hi

First of all is there any print call for Push and Pull Test after you have inserted the Parts?

Kindly consider:

· Is the hole size for inserting the parts is too tight and you have to use more force to insert the Parts.

· Can you bore the inserting hole slightly bigger a bit, so the inserting pin can use less force to insert in?

· Is the Inserting Pin out of spec, have you check the actual size of the inserting Parts?

Regards

Thanks for the response,

Actually this an 8 to 10 foot flat piece being inserted in a matching receptical. The present process is pounding in the piece with plastic blocks and hammers. A test to determine the insertion force needed exceeded 400 pounds. The final assembly is rectangular and requires the pieces inserted in 4 directions. In the assembly process the assembly is set on vertical so a clamp on the supporting side is not permissible or is too impractical.

I am thinking suppliers of hand held impact hammers do not publish impact force because the operator variable. e.g. one weights 120 pounds and another could weigh 200 pounds. So the actual impact depends on the pressure applied by the operator.

Re. question on test. The final assembly recieves a test that absolutely verifies the insertion is sufficient.

The hole size will vary +/- 10% of the nominal dimension.

±10% is a pretty huge variation. Out of interest, what's the material?

Extruded Aluminum

In this case the tappered end is held to +/-.005.

in all seriousnesses, in a close tolerance interference fit, introducing a silicon lubricate , aerokryoil or 3M , applied at the time of insertion may reduce the force required to press or tap fit. helps to resist corrosion as well

Thanks - I will look into the Lub idea.

With many air hammers models available on the market and having very close features, making the right choice when it comes to picking the perfect tool can be a bit confusing.

Here this article can help ;)

http://topproductguide.com/home-utilities/best-air-hammer-2017-reviews/