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What's the Stress in a Spring?

06/11/2009 1:52 PM

Using spring theory, how would I calculate the stress in a spring that is made from a very small diameter, tightly wound spring? I haven't found any equations for a complex problem like this besides trying to model it with FEA. It's not a spring actuating inside of another spring, it's substituting the material of a spring with that of a tightly wound spring. The small, tightly wound spring is made from SS 304 spring temper wire. The tightly wound spring is then wound onto a mandrel and heat set at 1100 degrees F. The final spring is a loosely wound spring.

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#1

Re: What's the Stress in a Spring?

06/11/2009 2:58 PM

Dunno, but it will be very floppy.
Can't you calculate the properties of the 'first' spring and then model a 'material' to simulate these properties (or just use the numbers) to model the 'final' spring?
I'd assume there would be very little stress in the first spring.

Or maybe you can just calculate the total lengthe of wire and ....errr....maybe I should quit while I'm behind...
Sorry if the above is bonkers
Del (note to self ... engage brain before posting)

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#2

Re: What's the Stress in a Spring?

06/11/2009 4:54 PM

Could you give a clearer explanation of what you think?

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#3

Re: What's the Stress in a Spring?

06/11/2009 7:47 PM

You may use spring theory and formulas to find the stress in a spring, no matter its size, because the scale of the loads, displacement, wire diameter will vary accordingly. There are some constants in the stress and displacement formulas for springs that vary according the wire size and curvature. I assume they are defined empirically. I would recommend a mechanical engineering manual, like the Mechanical Engineering Design by Shigley and Mischke. There's a number of tables and constants to check depending on the spring size, end configuration, and cross section shape. This is the answer for your initial question. The description you included after the question mentions that you are trying to manufacture a spring made from a 304 stainless steel "temper wire", and you wound the wire onto a mandrel and hope it will retain its final shape after heating and cooling. I see a problem here. 304 SS is austenitic. Its not to be submitted to heat treating, it will not transform upon cooling. Maybe you could relieve stress at high temperature, but it will not work like a low carbon or alloyed steel. Besides its not clear, I think that's why you're not getting your tight spring. My advice? Forget about the heat treating. Try to make it cold drawn, because a low hardness structure like that could benefit from the resulting effects. Wound it onto a smaller dia. mandrel, until it gets to the final diameter desired. If it does not work ( I dont know the sizes and other constraints for your spring), and still need to use stainless steel, and are able to choose another one, try a precipitation hardening steel like 17-4PH. Comes solubilized, can be easily worked cause is low carbon, and the post processing precipitation treatment gives very good high strengh material with virtually no deformation. Its resilience is notable, one of the best materials for springs.

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#4

Re: What's the Stress in a Spring?

06/11/2009 10:52 PM

This site has a nice little spring calculator.

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#5

Re: What's the Stress in a Spring?

06/12/2009 9:42 AM

Have you tried working with a spring manufacturer? I've had good luck in the past with them making custom springs.

Here's one site www.leespring.com

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#6

Re: What's the Stress in a Spring?

06/12/2009 2:30 PM

I appreciate all the responses and will look at different materials. I should clarify that this is a spring manufactured by winding a small diameter, tightly wound spring onto a mandrel to form a larger spring with an open pitch. This larger spring has a diameter approximately 10X of the smaller spring.

I used spring theory to calculate the theoretical spring constant and torsional spring stress of the smaller spring. I was then able to predict the larger spring's torsional yield stress based upon the actual tensile strength of the smaller spring.

To determine theoretical spring constant, I need the following values: Rigidity Modulus (G), mean spring diameter and number of active coils. For the smaller spring, I derived G from Poisson's Ratio and Young's Modulus. How do I derive G for the larger spring using the mechanical properties of the smaller spring? I could then plug this into the equation along with N and D for the larger spring.

Another question I have is how do I predict the ultimate tensile strength of the smaller spring? The Spring Theory equations apply to the torsional stress and the value predicts at what point the spring will yield and have permanent set. But spring theory doesn't predict the UTS. For example, the smaller spring should theoretically yield at .01lb, which it does on the tensile tester. But it has an experimental tensile strength of .16lb. From mechanics, torsional stress is 0.577 X yield tensile strength and yield tensile strength is 0.75 X UTS (for steel). By this convention, the theoretical spring torsional yield strength of 0.01lb would produce a theoretical yield tensile strength of 0.017lb and a theoretical ultimate tensile strength of 0.023lb. The theoretical spring UTS of 0.023lb is only 15% of the experimental spring UTS.

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#7
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Re: What's the Stress in a Spring?

06/13/2009 3:10 AM

how do I predict the ultimate tensile strength of the smaller spring?
You don't...you look up the material or measure it

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